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Stells [14]
3 years ago
10

Find an equation of the line through (2,7) and parallel to y=3x-6 Y=

Mathematics
1 answer:
Sliva [168]3 years ago
6 0

As we know the formula to calculate the line of equation is y - y1 = m (x - x1)

Where m is the slope. y1 is the first y co ordinate. x1 is the first x co ordinate.

Now we do know that the slope of parallel line is the same as the slope of the original line.

So parallel line slope is 3 so slope for our line is 3. Hence equation is y - 7 = 3 (x - 2) which becomes y = 3x + 1.


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1<br> What is the equation of the line parallel to 8x - 16y= -14 and passing through (3, 0)?
andreev551 [17]

Answer:

8x -16y = 24

Step-by-step explanation:

8x - 16y= -14

A parallel line (i.e. same slope) will be: 8x - 16y= c

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If it passes through (x, y) = (3, 0) ⇒ 24 - 0 =  c,

so equation is 8x -16y = 24

7 0
3 years ago
Let P=x^2+6<br> PLEASE SHOW WORK!!<br> 15 POINTS
stellarik [79]

Answer:

Step-by-step explanation:

P = x^2 + 6

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Solving for 4x^2:

P = x^2 +6

P - 6 = x^2

4(P - 6) = 4x^2

Substitution:

p^2 - 4p - 24 - 45 = 0\\p^2 -4p - 69 = 0

4 0
3 years ago
What substitution should be used to rewrite 4x12 – 5x6 – 14 = 0 as a quadratic equation? u = x2 u = x3      u = x6      u = x12
Arada [10]
Sent a picture of the solution to the problem (s).

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Read 2 more answers
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