Question

WILL GIVE A BRAINLEST AND 15PTS

Answer 1

Answer:2, 3, 5

Step-by-step explanation:

i just did it

Answer 2

we know that

In the right triangle of the figure

For the angle x

$cos(x)=\frac{a}{b}$

$x=cos^{-1}(\frac{a}{b})$

$sin(x)=\frac{c}{b}$

$x=sin^{-1}(\frac{c}{b})$

$tan(x)=\frac{c}{a}$

$x=tan^{-1}(\frac{c}{a})$

For the angle y

$cos(y)=\frac{c}{b}$

$y=cos^{-1}(\frac{c}{b})$

$sin(y)=\frac{a}{b}$

$y=sin^{-1}(\frac{a}{b})$

$tan(y)=\frac{a}{c}$

$y=tan^{-1}(\frac{a}{c})$

therefore

the answer is

$x=sin^{-1}(\frac{c}{b})$

$x=tan^{-1}(\frac{c}{a})$

$y=cos^{-1}(\frac{c}{b})$