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raketka [301]
3 years ago
12

The surface area of a rectangular prism is 2210 cm2. Two of the dimensions are 5 cm and 10 cm. Find the measure of the other dim

ension. Need help do not understand.
Mathematics
1 answer:
Vlad [161]3 years ago
6 0

The surface area of a rectangular prism is 2210 cm^2 Then the other dimension is 70.3 cm

<h3><u>Solution:</u></h3>

Given that surface area of rectangular prism is 2210 square centimeter

Also given that two of dimensions are 5 cm and 10 cm

To find: other dimension

<em><u>The total surface area of the rectangular prism is gievn as:</u></em>

\text {Total surface area }=2(lb+b h+h l)

Where, "l" is the length and "b" is the breadth and "h" is the height

The given values are:  l = 5cm and b = 10cm

On substituting the given values in formula we get,

\begin{array}{l}{2210=2(l \times b+b \times h+h \times l)} \\\\ {2210=2(5 \times 10+10 \times h+h \times 5)} \\\\ {2210=2(50+10 h+5 h)} \\\\ {1105=50+15 h} \\\\ {1055=15 h} \\\\ {h=70.3}\end{array}

Thus the other dimension is 70.3 cm

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Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

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The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

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