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3 years ago

What is 2 3/4+1 3/4?

Mathematics

1 answer:

expeople1 [14]3 years ago

6 0

Answer:

9/ 2

= 4 1/ 2

=4.5

Step-by-step explanation:

Step 1 of 2: Add.

Add

2 and 3 over 4

1 and 3 over 4

18 over 4

Step 1 of 2: Add.

Show the work

Step 2 of 2: Simplify.

Simplify

18 over 4

9 over 2

4 and 1 over 2

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How many pounds of cashew nuts worth 75 cents a pound must be mixed with 10 pounds of pecans worth $1.50 a pound to make a mixtu

Trava [24]

Let c represent the weight of cashews and p the weight of pecans.

Then c + 10 = total weight of the nut mixture.

An equation for the value of the mixture follows:

$1.50(10 lb) + $0.75c = (c+10)($1.00)

Solve this equation for c: 15 + .75c = c + 10. Subtract .75c from both sides:

15 = 1c - 0.75c + 10. Then 5=0.25c, and c = 5/0.25, or 20.

Need 20 lb of cashews.

Check: the pecans weigh 10 lb and are worth $1.50 per lb, so the total value of the pecans is $15. The total value of the cashews is (20 lb)($0.75/lb), or $15. Does (20 lb + 10 lb)($1/lb) = $15 + $15? Yes. So c= 20 lb is correct.

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3 years ago

What's the algebraic expression for the sum of v and 3

dangina [55]

The sum means addition
v + 3

6 0

2 years ago

Which of the following is a solution of the equation -5x + 2 = -13: answers: x=-9, x=75 x=3 x=-3

slamgirl [31]

Answer:

x= 3

Step-by-step explanation:

1. -5(3) + 2 = -13

2. -15 + 2 = -13 <em>A positive times a negative will always equal a negative</em>

3. -13 = -13 <em>Whenever you add anything to a negative number, the </em>

<em> number becomes smaller </em>

Ex: -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, ...........

<em>Although the number itself becomes smaller, its value </em>

<em> becomes bigger </em>

Hope this helps.

7 0

3 years ago

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

3 0

3 years ago

The volume of a cube is 125 cm^3. The area of a square is 64 cm^2. How does the lenghth of one edge of the cube compare to the l

anzhelika [568]

Answer:

One edge of the cube is 5 cm, one edge of the square is 8 cm, so the edge of the cube is 3 cm shorter than the edge of the square.

Step-by-step explanation:

<h3 /><h3>The volume of the cube is found by the formula </h3><h2>V = s³, </h2><h3>where s is the side length (called the edge in this problem)</h3><h3>Since V = 125 cm³, we can take the cube root of 125 to find the edge length.</h3><h3>The cube root of 125 is 5, ( 5³ = 125)</h3><h3>So the edge of the cube is 5 cm</h3><h3 /><h3>The are of a square is found by the formula </h3><h2>A = s² , </h2><h3>where s is the side length (called the edge in this problem) </h3><h3>Since A = 64 cm², we can take the square root of 64 to find the edge length.</h3><h3>The square root of 64 is 8 (8² = 84)</h3><h3>So the edge of the square is 8cm</h3><h3 /><h3>Comparing the two edges tells us that the edge of the cube is 3cm shorter than the edge of the square.</h3>

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2 years ago