Given:
Roots:
![\begin{gathered} -3+\sqrt[]{6} \\ -3-\sqrt[]{6} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20-3%2B%5Csqrt%5B%5D%7B6%7D%20%5C%5C%20-3-%5Csqrt%5B%5D%7B6%7D%20%5Cend%7Bgathered%7D)
Point: (-1,4)
To determine the equation of the parabola with the given roots and point, we find the missing values first.
Since the roots are given, we can say that the equation is:
![y=a(x+3-\sqrt[]{6})(x+3+\sqrt[]{6})](https://tex.z-dn.net/?f=y%3Da%28x%2B3-%5Csqrt%5B%5D%7B6%7D%29%28x%2B3%2B%5Csqrt%5B%5D%7B6%7D%29)
Next, we expand the terms.
Then, we plug in x= -1, and y=4 into the equation to get the value of a.
So,
That depends if the line is vertical or horizontal. If the line is vertical, the slope (steepness) of the line is undefined (this is because the x values across the entire line are the same). If the line is horizontal, the slope of the line is 0 (this is because the y values will always subtract to equal 0 when you use the form y1 - y2/x1 - x2 to find slope).
Hope this helps.
Answer: B on ed, i just took my test
Step-by-step explanation:
Answer is 55
Two ways you can approach this first you can subtract the three from the 10 and get 7. Square that to get 49. Now you know that x-6 has to equal 49 and the only option greater than 49 is 55
Second you can just take the problem step by step.
Subtract three from both sides.
Sqrt x-6 =7
Square both sides
X-6=7^2
x-6=49
Add six to each side
X=55
