Solve the equation for x. Sqrt X-6+3 = 10 x=1 x=13 x = 43 x= 55

Mathematics

1 answer:

Jlenok [28]3 years ago

8 0

Answer is 55
Two ways you can approach this first you can subtract the three from the 10 and get 7. Square that to get 49. Now you know that x-6 has to equal 49 and the only option greater than 49 is 55
Second you can just take the problem step by step.
Subtract three from both sides.
Sqrt x-6 =7
Square both sides
X-6=7^2
x-6=49
Add six to each side
X=55

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(A) $A=\left[\begin{array}{ccc}10&20&40\end{array}\right]$

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(A)

Matrix A represents the amount of each item ordered. It is 1 × 3 matrix.

Then matrix A is:

$A=\left[\begin{array}{ccc}10&20&40\end{array}\right]$

(B)

Next week the manager increases the order of all the products by 10%.

Then the amount of new orders are:

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Onions $=40\times [1+\frac{10}{100}]=40\times1.10=44$

Th matrix B represents the amount of each order for the next week. Then matrix B is:

$B=\left[\begin{array}{ccc}11&22&44\end{array}\right]$

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Add the two matrix A and B as follows:

$A+B=\left[\begin{array}{ccc}10&20&40\end{array}\right]+\left[\begin{array}{ccc}11&22&44\end{array}\right]\\=\left[\begin{array}{ccc}(10+11)&(20+22)&(40+44)\end{array}\right]\\=\left[\begin{array}{ccc}21&42&84\end{array}\right]$