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Sonja [21]
2 years ago
6

determine the equation of the parabola (simplified) with roots -3+sqrt6 and -3-sqrt6, and passing through the point (-1,4)

Mathematics
1 answer:
klio [65]2 years ago
6 0

Given:

Roots:

\begin{gathered} -3+\sqrt[]{6} \\ -3-\sqrt[]{6} \end{gathered}

Point: (-1,4)

To determine the equation of the parabola with the given roots and point, we find the missing values first.

Since the roots are given, we can say that the equation is:

y=a(x+3-\sqrt[]{6})(x+3+\sqrt[]{6})

Next, we expand the terms.

y=a(x^2+6x+3)

Then, we plug in x= -1, and y=4 into the equation to get the value of a.

\begin{gathered} y=a(x^2+6x+3) \\ 4=a((-1)^2+6(-1)+3) \\ \text{Simplify and rearrange} \\ 4=a(-2) \\ a=\frac{4}{-2} \\ a=-2 \end{gathered}

So,

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Step-by-step explanation:

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dedylja [7]

Answer:  \bold{(D)\ \dfrac{3}{4}-\dfrac{1}{4}x}

<u>Step-by-step explanation:</u>

\ \ \dfrac{3}{4}-x\bigg(\dfrac{1}{2}-\dfrac{5}{8}\bigg)+\bigg(-\dfrac{3}{8}x\bigg)\\\\\\=\dfrac{3}{4}\bigg(\dfrac{2}{2}\bigg)-x\bigg[\dfrac{1}{2}\bigg(\dfrac{4}{4}\bigg)-\dfrac{5}{8}\bigg]+\bigg(-\dfrac{3}{8}x\bigg)\\\\\\=\dfrac{6}{8}-x\bigg(\dfrac{4}{8}-\dfrac{5}{8}\bigg)-\dfrac{3}{8}x\\\\\\=\dfrac{6}{8}-x\bigg(-\dfrac{1}{8}\bigg)-\dfrac{3}{8}x\\\\\\=\dfrac{6}{8}+\dfrac{1}{8}x-\dfrac{3}{8}x\\\\\\=\dfrac{6}{8}-\dfrac{2}{8}x\\\\\\=\dfrac{3}{4}-\dfrac{1}{4}x\quad \text{(reduced both fractions)}

7 0
3 years ago
Find the unit price for each trail mix. cost is $6.00 and weight 3/4Lb
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3 years ago
In the inverse variation function, what happens to the output when the function's inputvalue is multiplied by 4?
Y_Kistochka [10]
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6 0
3 years ago
Read 2 more answers
Solve for x.
astra-53 [7]

Answer:

Option: C is correct.

x=\ln\sqrt{\dfrac{t+1}{1-t}}

Step-by-step explanation:

We are asked to solve for 'x' such that we are given a equation as:

\dfrac{e^x-e^{-x}}{e^x+e^{-x}}=t

This equation could also be written as:

e^x-e^{-x}=t(e^x+e^{-x})\\\\e^x-e^{-x}=te^x+te^{-x}\\\\e^x-te^x=te^{-x}+e^{-x}\\\\(1-t)e^x=(t+1)e^{-x}\\\\e^{2x}=\dfrac{t+1}{1-t}

on taking logarithmic function on both the sides we have:

2x=\ln (\dfrac{t+1}{1-t})

(since \ln (e^x)=x )

x=\dfrac{1}{2}\times \ln (\dfrac{t+1}{1-t})  

as we know \dfrac{1}{2}\times \ln b = \ln (b^\frac{1}{2})

Hence, we have: x=\ln\sqrt{\dfrac{t+1}{1-t}}

Hence, option C is correct.



5 0
3 years ago
Read 2 more answers
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