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statuscvo [17]
1 year ago
12

) At 1 november 2014 Brian owed $28,754 to his suppliers. During the year he paid his suppliers a

Business
1 answer:
RSB [31]1 year ago
8 0

Given the sums paid and owed to suppliers for the year ending on October 31, 2015, the value of Brian's credit purchase was $188, 409.

<h3>What was the credit purchase value ?</h3>

Brian's credit purchased in the year that ended 31 October 2015, can be found by the formula :
= Amount owed by Brian in 2014 + Amount paid by Brian in 2015 - Amount owed at 31 October 2015

Solving this equation would give us a value of :

= $ 28, 754 + 185, 844 - 26, 189

= $ 188 , 409

Find out more on credit purchases at brainly.com/question/14380289

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The jackson family is undecided about whether or nara buy a new car of the
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The question is incomplete. The complete question is :

The Jackson family is undecided about whether or not to buy a new car. If the probability is .9 that they will buy one, and if the probability is .3 that they will buy a Ford, and if the probability is .4 that they will purchase a car getting more than 20 miles per gallon, what is the probability that they will buy either a car getting more than 20 miles per gallon or a Ford, if all Fords get more than 20 miles per gallon?

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Given that :

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Probability of buying Ford = 0.3

That is, if Jackson family buy a car that is a ford car, $P(F) = 0.9 \times 0.3$

                                                                                                = 0.27

The probability for getting more than 20 miles per gallon = 0.4

That is if Jackson family buy a car that have more than 20 miles per gallon mileage, $P(20) = 0. 9 \times0.4=0.36$

The conditions

All of the car have more than 20 miles per gallon mileage.

It means that buying a ford car is subset of getting more than 20 miles per gallon.

$P(20 \text{ miles per gallon}\ \cap \ \text{Ford})=P(F)$

Therefore, the probability of buying a car either getting more than 20 miles per gallon or ford = $P(20 \text{ miles per gallon}\ \cup \ \text{Ford})$

Therefore,

$P(20 \text{ miles per gallon}\ \cup \ \text{Ford})=P(20) + P(F) - P(20 \text{ miles per gallon }\cap \ \text{Ford})$

$P(20 \text{ miles per gallon}\ \cup \ \text{Ford})=P(20) + P(F) - P(F)$

$P(20 \text{ miles per gallon}\ \cup \ \text{Ford})=P(20) $

                                                = 0.36

Thus the probability that Jackson family is buying a car either getting more than 20 miles per gallon or ford is 0.36

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3 years ago
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