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mr_godi [17]
1 year ago
14

The general equation for depreciation is given by y=a(1-r)^t where y=current value.

Mathematics
1 answer:
Jlenok [28]1 year ago
8 0

With the help of the given equation, we know that the automobile is worth $12528.15 after four years.

<h3>What are equations?</h3>
  • A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
  • a formula that expresses the connection between two expressions on each side of a sign.
  • Typically, it has a single variable and an equal sign.
  • Like this: 2x - 4 Equals 2.
  • In the above example, the variable x exists.

So, the equation of depreciation: y = A(1 - r)∧t

The current value is y.

A is the initial cost.

r is the depreciation rate.

t is the time in years, and

In four years, we must ascertain the present value.

Now,

y = $24000(1 - 0.15)⁴

y = 24000(0.85)⁴

y = 24000 × 0.52200625

y = 12528.15

Therefore, with the help of the given equation, we know that the automobile is worth $12528.15 after four years.

Know more about equations here:

brainly.com/question/28937794

#SPJ4

Complete question:
The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $

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l-length\\w-width\\\\\text{The formula of an area of a rectangle:}\ V=lw\\\\\text{We have the area}\ 540\ m^2\to lw=540\\\\\text{New rectangle}\\\\l-5-length\\w+5-width\\\\\text{We have the area}\ 540\ m^2+35\ m^2=575\ m^2\to (l-5)(w+5)=575\\\\\text{Therefore we have the system of equation:}\\\\\left\{\begin{array}{ccc}lw=540&\to w=\dfrac{540}{l}&(*)\\(l-5)(w+5)=575&&(**)\end{array}\right\\\\\text{Substitute}\ (*)\ \text{to}\ (**)

(l-5)\left(\dfrac{540}{l}+5\right)=575\qquad\text{use distributive property}\\\\(l)\left(\dfrac{540}{l}\right)+(5)(l)-(5)\left(\dfrac{540}{l}\right)-(5)(5)=575\\\\540+5l-\dfrac{2700}{l}-25=575\\\\515+5l-\dfrac{2700}{l}=575\qquad\text{subtract 575 from both sides}\\\\-60+5l-\dfrac{2700}{l}=0\qquad\text{multiply both sides by }\ l\neq0\\\\-60l+5l^2-2700=0\\\\5l^2-60l-2700=0\qquad\text{divide both sides by 5}\\\\l^2-12l-540=0\\\\l^2+30l-18l-540=0\\\\l(l+30)-18(l+30)=0\\\\(l+30)(l-18)=0\iff l+30=0\ \vee\ l-18=0\\\\l=-30

\text{Substitute the value of}\ l\ \text{to}\ (*):\\\\w=\dfrac{540}{18}\\\\\boxed{w=30\ cm}

Answer:\ \boxed{length=18\ cm,\ width=30\ cm}

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