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Arte-miy333 [17]
3 years ago
12

Ava has two frogs. This is 1/3 the number of frogs that Heather has. How many frogs does Heather have?

Mathematics
2 answers:
lesya692 [45]3 years ago
6 0

Answer:

2x3=6 and that the number of frogs heather has or you can do this Ava has 2 frogs and heather has 1/3 more then take the 2 and add it to the 1 and that makes three. then take both of the threes and add them together and you then have the same number of 6

Step-by-step explanation:


uranmaximum [27]3 years ago
5 0

Answer:

All in all, Ava has 6 frogs.

Step-by-step explanation (how i figured it out):

If 1/3 equals 2 frogs. Then times 2 by 3 which gives you six. I'm bad at explaining, but hoped this somewhat helped.



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3 out of five picks are orange . If 12 picks are orange , how many picks are there in all?
tekilochka [14]

20 picks in total .

8 0
3 years ago
A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%
OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

<u>Step :- (i)</u>

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

<u>95% of confidence intervals</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

<u>Step:-(ii)</u>

<u>The degrees of freedom γ=n-1 = 15-1=14</u>

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

<u>Conclusion</u>:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

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Hello,

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Answer B (but see the problem)
7 0
3 years ago
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podryga [215]

Answer:

For sure 34

Step-by-step explanation:

the red lines are the same length to each letter just add those.

8 0
3 years ago
‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ​
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Answer:

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hope i helped you!

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3 years ago
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