What is the slope intercept equation of this line?? please help
1 answer:
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Answer:
8 and 12
Step-by-step explanation:
Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means
AC/AB = CD/BD = 2/3
The perimeter is the sum of the side lengths, so is ...
25 = AB + BC + AC
25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.
20 = 5/3·AB
12 = AB
AC = 2/3·12 = 8
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<em>Alternate solution</em>
The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.
That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).
Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).
The remaining sides of the triangle are AB=12 and AC=8.
Answer:
The weighted average is of 69.94.
Step-by-step explanation:
Weighted average:
The weighed average is found multiplying each grade by its respective weight.
The grades, and weights are:
67 on the lab, with a weight of 23% = 0.23
69 on the first major test, with a weight is 21.5% = 0.215
85 on the second major test, with a weight is 21.5% = 0.215.
63 on the final exam, with a weight of 34% = 0.34.
Weighted average:
The weighted average is of 69.94.