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alexandr1967 [171]
1 year ago
8

On the right side, give a reason to justify each step made on the left

Mathematics
1 answer:
cestrela7 [59]1 year ago
8 0

Given that: step 1

3x+12=8x-18

step 2: subtract 3x both side

\begin{gathered} 3x+12-3x=8x-3x-18 \\ 12=5x-18 \end{gathered}

Step 3: Add 18 both side:

\begin{gathered} 12+18=5x-18+18 \\ 30=5x \end{gathered}

Step 4: divide both side by 5

\begin{gathered} \frac{30}{5}=\frac{5x}{5} \\ 6=x \end{gathered}

Step:6 The value of x is:

x=6

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A bucket contains one green block, one red block, and two yellow blocks. You choose one block from the bucket.
nalin [4]
A. 1/4; 2/4=1/2; 1/4
b. 1
c. 3/4. There are 4 blocks and 3 are not red
d. 1/4+3/4= 4/4=1


8 0
3 years ago
P(x) = 1 – 2x2 – 3x3 + 4x has what order?
nata0808 [166]

Answer:

3

Step-by-step explanation:

assuming you forgot you ^ mark after x x^3 would be the highest x order here making it the order for the equation.

5 0
2 years ago
Solve: (6x2 + 5x + 1) + (x + 2).
Mademuasel [1]

Answer:

6x+6x2+3

Step-by-step explanation:

6x2+5x+1+x+2

Combine 5x and x to get 6x.

6x2+6x+1+2

Add 1 and 2 to get 3.

6x2+6x+3

7 0
1 year ago
What is the equation of the line with an x-intercept of -2 and a y-intercept of 1?
vaieri [72.5K]

Answer:

the desired line is y = (1/2)x + 1

Step-by-step explanation:

Write these two points as (0, 1) and (-2, 0).

Now, as we go from (-2, 0) to (0, 1), x increases by 2 and y increases by 1.  Thus, the slope, m, of the desired line is m = rise / run = 1 / 2.

Then the desired line is y = (1/2)x + 1 (since b is already given as (0, 1) )

5 0
3 years ago
Please Help me!!!
drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

d=2t^3+5t^2-3

Displacement at t = 4 hours,

d(4)=2(4)^3+5(4)^2-3=205\ km

Velocity of particle is given by :

v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t

Velocity at t = 4 hours,

v=6(4)^2+10(4)=136\ km/h

Acceleration of the particle is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10

At t = 4 hours,

a=12(4)+10=58\ km/h^2

Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

7 0
3 years ago
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