The significance level shows that z approximately equals 1.41 for a p-value of 0.078642.
<h3>How to calculate the p-value?</h3>
Based on the complete question, the sample proportion for city A will be:
= 54/90 = 0.60
The sample proportion for city B will be:
= 63/90 = 0.70
Using the table given, it can be deduced that the test statistic value will be 1.41. Therefore, the p-value will be 0.078652 in the Excel function.
Since the p-value is greater than 0.05, then we fail to reject the null hypothesis that there is no difference in the commute time.
Learn more about significance level on:
brainly.com/question/4599596
