The speed of the sound wave in the medium, given the data is 3900 m
<h3>Velocity of a wave </h3>
The velocity of a wave is related to its frequency and wavelength according to the following equation:
Velocity (v) = wavelength (λ) × frequency (f)
v = λf
With the above formula, we can obtain the speed of the sound wave. Details below:
<h3>How to determine speed of the sound wave</h3>
The speed of the wave can be obtained as illustrated below:
- Frequency (f) = 600 Hz
- Wavelength (λ) = 6.5 m
- Velocity (v) =?
v = λf
v = 6.5 × 600
v = 3900 m
Thus, the speed of the sound wave in the medium is 3900 m
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Answer:
Acceleration = Final velocity-initial velocity/time
In m/s^2
a = 40000-0 /10
= 4000m/s
in km/h
a = 40/10÷360
= 1440km/h
Answer:
4.73V
Explanation:
Parameters given:
Radius of sphere = 65.7 cm = 0.657 m
Electric field = 7.2 * 10^5 V/m
Electric potential, V, is given in terms of Electric field as:
V = E * r
Where r = distance between charge and point of consideration.
Since we are considering a point just outside the spherical conductor:
V = 7.2 * 10^5 * 0.657
V = 4.73V
Answer:
23L
Explanation:
Given that:
Initial volume of water = 30mL
Final volume of water after an object was placed on it = 53mL
The volume object added which resulted in a rise to 5mL will be :
Final Volume of object - Initial volume of object
53 mL - 30mL = 23mL
Hence, volume of object added is 23 mL
