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butalik [34]
2 years ago
12

021. The hydrostatic pressure 'P' of a liquid column depends upon the

Physics
1 answer:
Lana71 [14]2 years ago
3 0

Answer:

A

Explanation:

hydrostatic pressure, P=hρg,

where 'h' is the ht of the liq column and ρ is the density of the liquid and 'g' is the effective acceleration, but as far as hydroSTATICS is concerned, g stands for the acceleration due to gravity

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A projectile is fired directly upward from the ground with an initial velocity of 112 f/sec its distance s above the ground afte
Travka [436]

Answer:

3.48 seconds

Explanation:

At maximum height Vf=0 m/s

Vf= Vi - g*t

⇒g*t= Vi

⇒t= Vi/g

⇒t= 112/32.17 sec

⇒ t= 3.48 s

so the projectile will achieve its maximum height in 3.48 seconds.

7 0
3 years ago
A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an
Dominik [7]

Answer:

position as a function of time is y = 0.05 × cos(9.9)t

Explanation:

given data

mass = 5 kg

length = 10 cm = 0.1 m

displaced = 5 cm

to find out

position as a function of time

solution

we will apply here equilibrium that is

mass × g = k × length

put here value and find k

k = \frac{5*9.8}{.01}

k = 490 N/m

and ω is

ω = \sqrt{\frac{k}{m} }

ω = \sqrt{\frac{490}{5} }

ω = 9.9

so here position w.r.t  time is

y = 0.05 × cosωt

y = 0.05 × cos(9.9)t

so position as a function of time is y = 0.05 × cos(9.9)t

8 0
3 years ago
How much power flows through a circuit with 5 amps and 120 volts?
Ainat [17]
600 watts may be your answer:)
3 0
3 years ago
A car is traveling in uniform circular motion on a section of flat roadway whose radius is . The road is slippery, and the car i
Alona [7]

Answer:

The smallest radius will be four (4) times the initial radius

Explanation:

The car maintains a constant angular speed. According to Newton's Second Law F = m a

1. F_{r}=m*A_{n}

2. A_{n}=\frac{v^2}{R_{p}}

Replacing 2 in 1

3. F_{r}=m*\frac{v^2}{R_{p}}

Where:

Fr= Frictional force

Rp= Initial Radius

An= Centripetal Acceleration

M= Mass

V= Velocity

Also we have that:

4. F_{r}=\mu *W=\mu*m*g

μ= Coefficient of friction between the car and the surface

M= Mass

W= Weight

G= Gravity

r is cleared from equation 3

5. R_{p}=m*\frac{v^2}{F_{r}}

Replacing 4 in 5

6. R_{p}=m*\frac{v^2}{\mu*m*g}

Simplifying

7. R_{p}=\frac{v^2}{\mu*g}

Now we have a new velocity equal to twice the initial velocity, We replace it by 2v in equation 7

8. R_{n}=\frac{(2v)^2}{\mu*g}

Computing

9. R_{n}=\frac{4v^2}{\mu*g}

Replacing 5 in 9

R_{n}=4*R_{p}

8 0
3 years ago
Which statement relates most directly to the second law?
alukav5142 [94]
Statement three i do believe

7 0
3 years ago
Read 2 more answers
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