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1 year ago

What is the greatest number of rectangles 6cm x 4cm that can be cut from a piece of metal measures 16 cm x 20 cm?

Mathematics

1 answer:

Dominik [7]1 year ago

7 0

Answer:

The greatest number of rectangles that can be cut from the piece of metal = 12

Explanation:

The dimension of the piece of metal = 16cm x 20cm

That is:

Length of the piece of metal = 20 cm

Width of the piece of metal = 16 cm

The dimension of the rectangle = 6cm x 4cm

Length of the rectangle = 6cm

Width of the rectangle = 4cm

The diagram below illustrates how the rectangles can be cut from the piece of metal

Considering the diagrams drawn above, and counting the rectangles formed, we can conclude that the greatest number of rectangles will be cut using the approach on the left, hence the greatest number of rectangles that can be cut is 12

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Evaluate.<br> (-5)5<br> Enter your answer in the box.

Klio2033 [76]

Answer:

The answer is -25

Step-by-step explanation:

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3 years ago

100/225 square feet of your bakery will be used as your storefront, where customers come to visit. the rest will be for storage

Angelina_Jolie [31]

Okay, so the answer is 5/9. “Someone” was correct. The subtracting of 100 from 225 came from the 100 already being used out of that 225. If you subtract that, you’re left with how much space left. Place those back into the fraction and simplify and you get our answer.

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4 years ago

Read 2 more answers

HELP PLEASE DUE IN 3 MINUTES

Alina [70]

It would be the first one

8 0

3 years ago

Ava wants to draw a parallelogram on the coordinate plane. She

wolverine [178]

Answer:

$k =(2,1)$

$JK = 2$

Step-by-step explanation:

Given

$J = (0,1)$ ---- $(x_1,y_1)$

$H = (1,-2)$ --- $(x_2,y_2)$

$I = (3,-2)$ --- $(x_3,y_3)$

See attachment for grid

Solving (a): The coordinates of K

The parallelogram has the following diagonals: IJ and HK

Diagonals bisect one another. So:

Midpoint of IJ = Midpoint of HK

This gives:

$\frac{1}{2}(I + J) = \frac{1}{2}(H+K)$

$\frac{1}{2}(x_3+x_1,y_3+y_1) = \frac{1}{2}(x_2+x,y_2+y)$

$\frac{1}{2}(3+0,-2+1) = \frac{1}{2}(1+x,-2+y)$

$\frac{1}{2}(3,-1) = \frac{1}{2}(1+x,-2+y)$

Multiply through by 2

$(3,-1) = (1+x,-2+y)$

By comparison:

$1 + x = 3$

$-2 + y = -1$

Solve for x and y

$x = 3 - 1 =2$

$y = -1 +2 = 1$

So, the coordinates of k is:

$k =(2,1)$

The length of JK is calculated using distance (d) formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

$J = (0,1)$ ---- $(x_1,y_1)$

$k =(2,1)$ ---- $(x_2,y_2)$

So:

$d = \sqrt{(0 - 2)^2 + (1 - 1)^2$

$d = \sqrt{(- 2)^2 + (0)^2$

$d = \sqrt{4 + 0$

$d = \sqrt{4$

$d = 2$

Hence:

$JK = 2$

8 0

3 years ago

Can someone help me solve (x+18)^(1/2)+2=x

____ [38]

Lets solve your equation step by step:
(x+18)^1/2+2=x
step 1:Add -2 to both sides:
(x+18)^1/2+2-2=x+-2
(x+18^)1/2=x-2
step 2:solve exponent
(x+18)^1/2=x-2
((x+18)^1/2)^2=(x-2)^2
x+18=x^2-4x+4
x+18-(x^2-4x+4)=x^2-4x+4-(x^2-4x+4) (subtract x^2-4x+4 from both sides)
-x^2+5x+14=0
(-x-2)(x-7)=0(factor left side of equation)
-x-2=0 or x-7=0 (set factors equal to zero)
x=-2 or x=7

check answers:(plug them in to make sure they work )
x=-2(doesn't work in original equation)
x=7(works in original equation)

6 0

3 years ago