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saul85 [17]
2 years ago
8

How do you solve for x in this using trignometric ratios

Mathematics
1 answer:
stellarik [79]2 years ago
7 0

Answer:

x= 23.775.

Step-by-step explanation:

\text{We have} \\\cos(18\textdegree) = \frac{x}{25} \\\Rightarrow x= 25\cos(18\textdegree)\\\Rightarrow x= 25 \times 0.951\\\Rightarrow x= 23.775.

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Two groups of workers are painting a bridge in the bay. The first group is responsible for painting the north side of the bridge
artcher [175]

Answer:

They will each have painted 8 km. This goal will be met on Day 4.

Step-by-step explanation:

Group A | Group B

Start: 2   | Start: 5                               Day 1

2 + 2 = 4 | 5 + 1 = 6                            Day 2

4 + 2 = 6 | 6 + 1 = 7                             Day 3

6 + 2 = 8 | 7 + 1 = 8                            Day 4

4 0
3 years ago
What is the constant of vanation,<br>of the line y = for through (3.18) and (5,30)?​
Naily [24]

the constant of variation or namely its slope will be

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{18})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{30}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{30-18}{5-3}\implies \cfrac{12}{2}\implies 6

8 0
2 years ago
If Val walls 1/2 mile for every 3/4 mile she runs if she walked 2 miles how many miles did she run
Usimov [2.4K]
Answer: She ran 3 miles

Explanation:
1/2 miles walked) • X = (2 Miles walked)

X= 4

4 • 3/4 miles ran = 12/4 miles ran = 3 miles ran.

6 0
2 years ago
I will give brainiest to whoever answers correctly !!
son4ous [18]
August 22nd should be the date 120 days after April 24th
7 0
3 years ago
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

6 0
2 years ago
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