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stealth61 [152]
10 months ago
9

All you need is in the photo I DON'T WANT STEP BY STEP ANSWER FAST please fdsd

Mathematics
1 answer:
Brut [27]10 months ago
6 0

We have the following:

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ a=5 \\ b=0 \\ c=-80 \end{gathered}

replacing:

\begin{gathered} x=\frac{-0\pm\sqrt[]{0^2-4\cdot5\cdot-80}}{2\cdot5}=\frac{\pm\sqrt[]{1600}}{10}=\frac{\pm40}{10}=\pm4 \\ x_1=4 \\ x_2=-4 \end{gathered}

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