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UkoKoshka [18]
3 years ago
14

Graph a line with a slope of -3/4 that contains the point (2,3) ?

Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

First place a mark at your point. (x=2, y=3)

Step-by-step explanation:

Now when you look at the -3/4 that is called your rise over run so you will go down 3 and over 4 so your next point will be at (x=0, y=6) and then you connect your dots to make a line.

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Can anyone help me with this answer.
Kitty [74]

Answer:

<u>27 cm²</u>

Step-by-step explanation:

Shaded Area = Area ABCE - Area AED

  • S.A. = 6 x 6 - 1/2 x 3 x 6 [DE = 1/2AB = 1/2 X 6 = 3]
  • S.A. = 36 - 9
  • S.A. = <u>27 cm²</u>
8 0
2 years ago
Read 2 more answers
What is 1 × 10 − 3 written in standard form? math
ehidna [41]

Answer:

7

Step-by-step explanation:

When working with order of operations, use the acronym 'PEMDAS' (Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

The equation should basically be done in that order.

There are no parenthesis,

no exponents,

But there IS multiplication.

1 x 10 = 10.

So now, what is left over is 10 - 3.

There addition, but there IS subtraction.

10 - 3 = 7.

7 is what is left over.

Therefore, 1 x 10 - 3 in standard form is 7.

8 0
3 years ago
Easy math for smart people problem: 7w-6=3(w+6)
LenKa [72]

Answer:

<h2>w=6</h2>

Step-by-step explanation:

7w-6=3w+18                     I expanded the bracket

+6 on both sides

7w=3w+24

-3w on both sides

4w=24

divide both sides by 4

w=6

5 0
2 years ago
Choose the pair(s) of integers that can be substituted into the equation ax2 - 6x + c = 0 so that it has two real solutions.
Maksim231197 [3]

The options are not provided, but method is stated below

Answer:

Quadratic equation ax2 - 6x + c = 0

options would be given for a and c

  1. substitute a and c
  2. check for Discriminant
  3.  b^2 - 4ac \geq  0
  4. 36 -4ac \geq 0

These conditions will fetch us the result required among the options.

Note : the \geq sign will give us the result for Two real unequal solutions and two real equal solutions.  If we only need Real unequal solutions we only use > sign instead of \geq

4 0
3 years ago
PLSSSSSSSSSS HELPPPPPP MEEEEEEE, WILL RATE YOU BRAINLIEST!!!!!!!!!!!!!!
Artemon [7]
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2

The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2

Hope this helps:) plz mark brainiest i would really apperciate it
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5 0
3 years ago
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