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UkoKoshka [18]
3 years ago
14

Graph a line with a slope of -3/4 that contains the point (2,3) ?

Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

First place a mark at your point. (x=2, y=3)

Step-by-step explanation:

Now when you look at the -3/4 that is called your rise over run so you will go down 3 and over 4 so your next point will be at (x=0, y=6) and then you connect your dots to make a line.

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Suppose a change of coordinates T:R2→R2 from the uv-plane to the xy-plane is given by x=e−2ucos(5v), y=e−2usin(5v). Find the abs
anzhelika [568]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The solution is  \frac{\delta  (x,y)}{\delta (u, v)} | = 10e^{-4u}

Step-by-step explanation:

From the question we are told that

        x =  e^{-2a} cos (5v)

and  y  =  e^{-2a} sin(5v)

Generally the absolute value of the determinant of the Jacobian for this change of coordinates is mathematically evaluated as

     | \frac{\delta  (x,y)}{\delta (u, v)} | =  | \ det \left[\begin{array}{ccc}{\frac{\delta x}{\delta u} }&{\frac{\delta x}{\delta v} }\\\frac{\delta y}{\delta u}&\frac{\delta y}{\delta v}\end{array}\right] |

        = |\ det\ \left[\begin{array}{ccc}{-2e^{-2u} cos(5v)}&{-5e^{-2u} sin(5v)}\\{-2e^{-2u} sin(5v)}&{-2e^{-2u} cos(5v)}\end{array}\right]  |

Let \   a =  -2e^{-2u} cos(5v),  \\ b=-2e^{-2u} sin(5v),\\c =-2e^{-2u} sin(5v),\\d=-2e^{-2u} cos(5v)

So

     \frac{\delta  (x,y)}{\delta (u, v)} | = |det  \left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] |

=>    \frac{\delta  (x,y)}{\delta (u, v)} | = | a *  b  - c* d |

substituting for a, b, c,d

=>    \frac{\delta  (x,y)}{\delta (u, v)} | =  | -10 (e^{-2u})^2 cos^2 (5v) - 10 e^{-4u} sin^2(5v)|

=>   \frac{\delta  (x,y)}{\delta (u, v)} | =  | -10 e^{-4u} (cos^2 (5v)   + sin^2 (5v))|

=>  \frac{\delta  (x,y)}{\delta (u, v)} | = 10e^{-4u}

7 0
3 years ago
Simplify using order of operations<br>5.3-6.3+5²​
prohojiy [21]

IT SHOULD BE 24 IF NOT IM SRRY

6 0
2 years ago
Read 2 more answers
-3/4÷-1/2<br><br>pls help armieee​
PilotLPTM [1.2K]

Answer:

exact form : 3/2

decimal form 1.5

mixed number form 1 1/2

8 0
3 years ago
A bakery sold a total of 400 cupcakes in a day, and 43% of them were vanilla flavored. how many of the cupcakes sold that day we
garik1379 [7]

The number of the cupcakes sold that day that were vanilla flavored is 172.

<h3>How do we calculate a number from a percentage?</h3>

The number of the cupcakes sold that day that were vanilla flavored can be calculated using the following formula:

Number of vanilla flavored cupcakes sold = Total number of cupcakes sold * Percentage that were vanilla flavored .............. (1)

Substituting the relevant values into equation (1), we have:

Number of vanilla flavored cupcakes sold = 400 * 43% = 172

Learn more about percentages here: brainly.com/question/14801224.

#SPJ1

7 0
2 years ago
Given an equation x3 - 8x2 - 9x + 72 = 0, find the zeros.
sveta [45]

Answer:

= 28/3

Step-by-step explanation:

Let's solve your equation step-by-step.

x(3)−(8)(2)−9x+72=0

Step 1: Simplify both sides of the equation.

x(3)−(8)(2)−9x+72=0

3x+−16+−9x+72=0

(3x+−9x)+(−16+72)=0(Combine Like Terms)

−6x+56=0

−6x+56=0

Step 2: Subtract 56 from both sides.

−6x+56−56=0−56

−6x=−56

Step 3: Divide both sides by -6.

−6x

−6

=

−56

−6

x=

28

3

Answer:

x=

28

3

7 0
3 years ago
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