Answer:
Option B. (x+3) ^2+(y+4)^2=25
Step-by-step explanation:
we know that
The equation of the circle in standard form is equal to
![(x-h)^{2}+(y-k)^{2}=r^{2}](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%3Dr%5E%7B2%7D)
where
(h,k) is the center and r is the radius
step 1
Find the radius of the circle
Remember that the distance of the center and any point on the circle is equal to the radius of the circle
so
Find the distance between the points (-3,-4) and (0,0)
the formula to calculate the distance between two points is equal to
![d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y2-y1%29%5E%7B2%7D%2B%28x2-x1%29%5E%7B2%7D%7D)
substitute
![r=\sqrt{(0+4)^{2}+(0+3)^{2}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%280%2B4%29%5E%7B2%7D%2B%280%2B3%29%5E%7B2%7D%7D)
![r=\sqrt{(4)^{2}+(3)^{2}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%284%29%5E%7B2%7D%2B%283%29%5E%7B2%7D%7D)
![r=\sqrt{25}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B25%7D)
![r=5\ units](https://tex.z-dn.net/?f=r%3D5%5C%20units)
step 2
Find the equation of the circle
![(x-h)^{2}+(y-k)^{2}=r^{2}](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%3Dr%5E%7B2%7D)
the center is the point (-3,-4) and the radius is r=5 units
substitute
![(x+3)^{2}+(y+4)^{2}=5^{2}](https://tex.z-dn.net/?f=%28x%2B3%29%5E%7B2%7D%2B%28y%2B4%29%5E%7B2%7D%3D5%5E%7B2%7D)
![(x+3)^{2}+(y+4)^{2}=25](https://tex.z-dn.net/?f=%28x%2B3%29%5E%7B2%7D%2B%28y%2B4%29%5E%7B2%7D%3D25)
Quartile or interquartile.
Answer:
z=3
Step-by-step explanation:
-12=-8z+12
-12-12=-8z
-24=-8z
-24/-8=z
z=24/8
3=z
z=3
Lo siento, español no es mi primer lengua, pero trataré ayudar. ¿Qué significa L1, L2, y L3? No recuerdo.
Necesita multiplicar
x-3 • x+2
x-2 • x-1
Pero, obtendrías esto, y no ayudaría
x^2-6 = x^2+2
Es imposible resolver para x con eso.
Creo que la respuesta es e. no existe tal valor para x