MN = 6 in
add the parts of the ratio, 1 + 2 + 3 = 6
divide AB by 6 to find 1 part of the ratio
= 3 ← 1 part
AM = 3 in ← 1 part
MN = 2 × 3 = 6 in ← 2 parts
NB = 3 × 3 = 9 in ← 3 parts
and 3 + 6 + 9 = 18 in = AB
Answer:
B(6 , -11)
Step-by-step explanation:
(x-2 , y+3) = (4 , -8)
Compare the x & y co ordinates
x - 2 = 4 ; y + 3 = -8
x = 4 +2 ; y = -8 - 3
x = 6 ; y = -11
B(6 , -11)
Vertical angles 2 and 5, 1 and 6, 3 and 8, 7 and 4
linear pair 1 and 5, 5 and 6, 6 and 2, 2 and 1, and also 3 and 7, 7 and 8, 8 and 4, 4 and 3
congruent angles - all vertical pairs are congruent angles
2 congruent to 5, 1 congruent to 6, 3 congruent to 8, 7 congruent to 4
The area of the surface given by is 1. In terms of a surface integral, we have
By multiplying each component in by 5, we have
and the same goes for the derivative with respect to . Then the area of the surface given by is
Answer
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