Answer:
Is the -8x2 a -8x squared? Because the answer of this problem can be different.
Step-by-step explanation:
Yes it x2 is a factor because at some point and time 2x would cross 4x
There are 260 calories in the whole can.
to get this you multiply the calories in one serving by the amount of total servings, in this case 2.
Answer:
There is no mode
Step-by-step explanation:
Looks like we're given

which in three dimensions could be expressed as

and this has curl

which confirms the two-dimensional curl is 0.
It also looks like the region
is the disk
. Green's theorem says the integral of
along the boundary of
is equal to the integral of the two-dimensional curl of
over the interior of
:

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of
by


with
. Then

