An = a1 + (n - 1)(d)
Where a1 is the first term and d is the common difference.
First find d, the common difference.
24, ____, 32
a3 a4 a5
Subtract 32-24 = 8
Subtract a5 - a3 = 2
Divide 8/2 = 4
d = 4
Use d and one of the values they give us to find a1.
a3 = 24
24 = a1 + (3 - 1)(4)
24 = a1 + 2(4)
24 = a1 + 8
Subtract 8 from both sides
16 = a1
an = 16 + (n - 1)(4)
Can also be written
an = 16 + 4n - 4
an = 4n + 12
Answer:
B
Step-by-step explanation:
First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial 
. We can now use the quadratic formula to solve.
Remember that the quadratic formula is
Substitute the numbers from the equation into the formula.
Simplify:
Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with 
.
Hope this helps!
So, in order to find out which ordered pairs are the solutions to the given inequality above, we just have to plug in the given values.
Lets take option A.
2 > -3(0) + 2
2 > 0 + 2
2 > 2 ---- 2 is not greater than 2, which makes this ordered pair not a solution to the given inequality.
So, do the same with the rest of the ordered pairs.
So the ordered pairs that are the solutions would only be options C, E and F. Hope that answer helps.
It’s a Trapezium (also called Trapezoid)
