All categories

1 year ago

An envelope is 15 centimeters wide, and it measures 17 centimeters along the diagonal. The envelope is __ centimeters tall.

Mathematics

1 answer:

PSYCHO15rus [73]1 year ago

8 0

An envelope is rectangular in shape.

Given the width = 15cm, and diagonal = 17cm

Let h represent the tall length of the envelope

Applying Pythagoras theorem, we have

$\begin{gathered} 17^2=15^2+h^2 \\ 289=225+h^2 \\ h^2=289-225 \\ h^2=64 \\ h=\sqrt[]{64} \\ h=8\operatorname{cm} \end{gathered}$

The envelope is 8cm tall

You might be interested in

On expression that is equal to 5.1 - 5.9

Nastasia [14]

Answer: 10.2-11.8

Step-by-step explanation:

im guessing that the question is "write one expression that is equal to 5.1 - 5.9" i would make it simple as possible and double both numbers to get 10.2-11.8"

8 0

3 years ago

Read 2 more answers

An article in the local paper states that 30% of the students at Oak Grove Middle School earned a place on the silver honor roll

den301095 [7]

In order to figure out 30% of 920 you multiply 920 by 0.3

920 * 0.3 = 276

8 0

3 years ago

An open box is to be made by using a piece of sheet metal with the dimensions of 4m by 2m. Determine the dimensions the box shou

Natali5045456 [20]

Answer:

Dimensions: 0.4 by 3.2 by 1.2

Step-by-step explanation:

I'm assuming here that we are cutting out squares out of each of the metal's corners:

Let x = the length of each cut-out square,

Each base (of the desired net square folded) is 4-2x, and 2-2x respectively,

Volume = x(4-2x)(2-2x)

= 4x^3 - 12x + 8x

Now we take the derivative:

$\frac{d}{dx}\left[4x^3-12x^2+8x\right]\\\\= \frac{d}{dx}\left(4x^3\right)-\frac{d}{dx}\left(12x^2\right)+\frac{d}{dx}\left(8x\right)\\\\= 12x^2-24x+8$

We equate to 0 (0 for max volume), and solve using the quadratic formula:

$12x^2-24x+8=0,\\\\x_{1,\:2}=\frac{-\left(-24\right)\pm \sqrt{\left(-24\right)^2-4\cdot \:12\cdot \:8}}{2\cdot \:12}\\\\= \frac{-\left(-24\right)\pm \:8\sqrt{3}}{2\cdot \:12}\\\\\mathrm{Separate\:the\:solutions}:\\\\x_1=\frac{-\left(-24\right)+8\sqrt{3}}{2\cdot \:12},\:x_2=\frac{-\left(-24\right)-8\sqrt{3}}{2\cdot \:12}\\\\x =\frac{3+\sqrt{3}}{3},\:x=\frac{3-\sqrt{3}}{3}\\\\x=1.57735\dots ,\:x=0.42264\dots$

So we approximate the side lengths to be 1.6 and 0.4 respectively. But when we plug in 1.6 for x, we get the volume as negative. Therefore x has to be 0.4.

Side lengths: 0.4, 4-2(0.4) => 3.2, 2-2(0.4) => 1.2

7 0

3 years ago

Which sentence most clearly describes medium? O A. The presence of adventure elements in a mystery was obviously surprising O B.

ryzh [129]

I’m sorry running a little bit late but I’m just

7 0

3 years ago

Evaluate the expression for q = –17 and r = 16. Simplify your answer.<br> r/q+r<br> /=divide

kirill [66]

Answer:

i tried many times but l didn't get the best ans