The power increases by 21% per hour. 21% written as a decimal is 0.21.
Because it increases you would multiply the starting value by 1.21 times the number of hours (t).
That needs to be less than or equal to 100,00
The equation would be:
C: 15,040(1.21)t ≤ 100,000
To find the slope of the above equation, it is easiest to put it into slope-intercept form, y=mx + b, where the variable m represents the slope. To do this, we must isolate the variable y on the left side of the equation by using the reverse order of operations. First, we should subtract 3x from both sides of the equation.
3x + 6y = 9
6y = -3x + 9
Next, we should divide both sides of the equation by 6 to undo the coefficent of 6 on the variable y.
y = -1/2x + 3/2
Therefore, the slope of the line is -1/2 (the coefficient of the variable x in slope-intercept form).
Hope this helps!
<h3>
Answer: Choice B</h3>
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Explanation:
The rule we use is
![\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m](https://tex.z-dn.net/?f=%5CLarge%20a%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20%5Cleft%28%5Csqrt%5Bn%5D%7Ba%7D%5Cright%29%5Em)
where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).
So for instance,
![\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3](https://tex.z-dn.net/?f=%5CLarge%202%5E%7B3%2F4%7D%20%3D%20%5Csqrt%5B4%5D%7B2%5E3%7D%20%3D%20%5Cleft%28%5Csqrt%5B4%5D%7B2%7D%5Cright%29%5E3)
or in this case,
![\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5](https://tex.z-dn.net/?f=%5CLarge%20t%5E%7B5%2F8%7D%20%3D%20%5Csqrt%5B8%5D%7Bt%5E5%7D%20%3D%20%5Cleft%28%5Csqrt%5B8%5D%7Bt%7D%5Cright%29%5E5)
8a^2 + 3a^2
11a^2
since both have a^2 you only have to add the coefficients
Answer:
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Step-by-step explanation:
well thanks for the free points :)
