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Hoochie [10]
1 year ago
12

For this equation, tell whether it is always true, sometimes true, or nevertrue.

Mathematics
1 answer:
dybincka [34]1 year ago
3 0

To answer the question we make the sum on the left side of the equation:

\begin{gathered} \frac{1}{2}y+5=\frac{y+10}{2} \\ \frac{y}{2}+5=\frac{y+10}{2} \\ \frac{y}{2}+\frac{10}{2}=\frac{y+10}{2} \\ \frac{y+10}{2}=\frac{y+10}{2} \end{gathered}

Since both sides are exactly the same. this equation is always true.

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Find the area of the parallaogram to the nearest tenth
GuDViN [60]

Answer:

sorry I think yr question is incomplete.

u forget to add picture.

<h3>stay safe healthy and happy.</h3>

6 0
3 years ago
Help me on this please
SIZIF [17.4K]

The answer is 3214

3 is equivelant to 0.74

2 is equivelant to 0.88...

1 is equivelant to 7

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5 0
3 years ago
A 2?-ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles.
navik [9.2K]

Answer: A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

Step-by-step explanation:

Since we have given that

Radius of inner circle = 57 ft

As we know the formula for "Circumference of circle":

Distance=Circumference=2\pi r\\\\Distance=2\times \frac{22}{7}\times 57\\\\Distance=358.28\ Ft

Since we have also mentioned that there is 2 feet wide circular track for a camera dolly.

So, Radius of outer circle will be given as

57+2\\=59\ ft

So, Distance = Circumference is given by

Distance=2\pi R\\\\Distance=2\times \frac{22}{7}\times 59\\\\Distance=370.85\ ft

Hence, Difference between the outer rail travel than a wheel on the inner rail travel is given by

370.85-358.28\\\\=12.57\ ft

Therefore, A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

7 0
3 years ago
Solve for x. 16x - 5 = 18x - 2  and Solve for x.<br><br>13x + 7 = 5x - 20
Naily [24]
The answer to the question

7 0
3 years ago
A sandbag is released from a hot air balloon that is 400 ft above the ground. Using the falling object model, h = −16t^2 + s, wh
Bogdan [553]

Answer:

  B. 5 seconds

Step-by-step explanation:

A graphing calculator shows the answer easily.

__

h(t) = 0 = -16t^2 +400

t = √(400/16) = 5

It will take 5 seconds for the sandbag to hit the ground.

7 0
3 years ago
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