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BlackZzzverrR [31]
3 years ago
6

7 divided by the quantity a minus 6

Mathematics
1 answer:
Nesterboy [21]3 years ago
5 0

Answer:

7 ÷ (a - 6)

Step-by-step explanation:

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2(5c+ 2) - 2c = 3(2c + 3) + 7
Mademuasel [1]

Answer:

c = 6

Step-by-step explanation:

Step 1: Write equation

2(5c + 2) - 2c = 3(2c + 3) + 7

Step 2: Solve for <em>c</em>

  1. Distribute: 10c + 4 - 2c = 6c + 9 + 7
  2. Combine like terms: 8c + 4 = 6c + 16
  3. Subtract 6c on both sides: 2c + 4 = 16
  4. Subtract 4 on both sides: 2c = 12
  5. Divide both sides by 2: c = 6
8 0
3 years ago
Read 2 more answers
Select the two statistical questions that Gary could ask,
lakkis [162]

Answer:

the 2 statistical questions are B and C

4 0
3 years ago
Y=3x-7 Complete the missing value in the solution to the equation. (1,_)
creativ13 [48]

Answer:

minus 4

Step-by-step explanation:

answers in the photo thanks

6 0
3 years ago
is picking out some movies to rent, primarily interested in horror films and comedies. He has narrowed down his selections to 15
tigry1 [53]

Answer: 31,365

Step-by-step explanation:

Given : The number of horror films = 15

The number of comedies = 18

Then , the number of different combinations of 4 movies can he rent if he wants at least two comedies is given by :-

^{18}C_2\times ^{15}C_2+^{18}C_3\times ^{15}C_1+^{18}C_4\times ^{15}C_0\\\\=\dfrac{18!}{2!(18-2)!}\times\dfrac{15!}{2!(15-2)!}+\dfrac{18!}{3!(18-3)!}\times\dfrac{15!}{1!(15-1)!}+\dfrac{18!}{4!(18-4)!}\times\dfrac{15!}{0!(15-0)!}\\\\=16065+12240+3060=31365

Hence, the  number of different combinations of 4 movies can he rent if he wants at least two comedies = 31,365

7 0
3 years ago
Please help me. I’m trying to make my mom happy
poizon [28]

Answer:

I think D is the answer.

Step-by-step explanation:

❤️❤️❤️❤️❤️❤️.

6 0
2 years ago
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