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2 years ago

Whoever helps me with this question gets points

Mathematics

1 answer:

ohaa [14]2 years ago

4 0

Answer:

All triangles are open figures.f (60-60-60)

All triangles have 3 sides that are equal in length.f(3,4,5)

Only some triangles have 1 right angle.t

All triangles are polygons.t

All triangles have 3 angles.t

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I need help plzzzzzzz answer this for ten points????

Inessa05 [86]

Answer:

The first one: Kilo-liters to milliliters.

When converting on the metric table, always remember:

Converting from larger to smaller you multiply. Converting from smaller to larger, you divide.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Given: What type of angles are ∠2 and ∠3 are adjacent angles.

lubasha [3.4K]

The correct answer is: [D]: "supplementary angles, 180° " .
_____________________________________________________
Note:

Choices:
_____________________________________________________
[B]: "complementary angles, 180° " ; and:
_____________________________________________________
[C]: "supplementary angles, 90° " ;
_____________________________________________________
can automatically be ruled out ; since by definition:

→ Complementary angles always add up to 90° — NOT 180° ;
and: supplementary angles always add up to 180° — NOT 90° .
_____________________________________________________
Note: "Adjacent angles" refer to "supplementary angles" ; which, by definition add up to 180° . Futhermore, looking at the image provided,

we see that ∠1 and ∠2 are, in fact "adjacent" and that ∠1 and ∠2 comprise the entire portion of a "straight line" (being intersected by a transversal)" ;

and as such; ∠1 and ∠2 are supplementary angles—

and as such—add up to 180° .

(which rules out: Choice [A]: "complementary angles, 90°) ;

→ and demonstrates the correct answer:
______________________________________________________
Answer choice: [D]: "supplementary angles, 180° " .
 ______________________________________________________

5 0

3 years ago

:( help me please,,, if ur good at mean, median mode and range

Verdich [7]

Answer:

ill help when you give the problem lol

Step-by-step explanation:

4 0

3 years ago

PLSS ANSWER MY QUESTION

Taya2010 [7]

Answer:

1) Area of frame: $140cm^2$ ; Area of picture: $40cm^2$ ; Total Area: $180cm^2$ .

2) Area 1 = $48cm^2$ ; Area 2 = $12cm^2$ ; total area = $60cm^2$ [first answer line : $60cm^2$ ]

Step-by-step explanation:

1. So to answer this question, you have to find the inner photo area first (which you will then subtract from the overall rectangle area to get the photo frame area).

To find area, you multiply length x width. For this question, there are not enough measurements given to initially multiply length and width. So, assuming that the photo is centered on the frame and the frame width is consistent along all sides, you find the difference between the overall length (12) and the picture length (5).

12 - 5 = 7

The leftover area (outside of the picture) is 7 cm (half of seven on both sides), so one side can be assumed to be : 3.5 cm

this means that 15 cm - 3.5 cm of both sides lengths (difference between the two lengths given) is the height of the photo, 15 - 3.5(2) = 8

So, the dimensions/measurements of the photo are 5 cm by 8 cm.

This means that the inner photo area is 40 (5 x 8) cm

The area of the frame will be the area of the total rectangle [12 x 15] - the inner photo area [40]. [ (12)(15) - 40 ]

[180 - 40] = 140 cm

(area is measured in squared units, so the area of the frame should be written as $140cm^{2}$ ; and the area of the photo should be written as $40cm^{2}$ )

The total area is the entire area of the rectangle: (12)(15) = 180. (This should be written as $180cm^2$ )

--------------------------------------

2) Finding the area of a shape that isn't a simple rectangle is easier if you separate the shape into smaller rectangles. I will separate the two rectangles into 4 x 12 and 2 x 6 [6 cm would be the remaining side length if you remove the length of 4].

{you can separate the shape in multiple ways, so my answer is only one answer to this problem out of other splits.}

as mentioned, the area is length x width.

4 x 12 = 48.

2 x 6 = 12. Once again, you should write area in squared units.

(the area 1 should be written as $48cm^{2}$ ; the area 2 should be written as $12cm^2$ )

you can combine the separated areas (add them) to find the total area. 48 + 12 = 60.

(the total area should be written in squared units also, so the total area should be written as: $60cm^2$ )

The area of the figure is $60cm^2$

8 0

2 years ago

The height of a triangle is 8 centimeters greater than half its base. The area of the triangle is 48 square centimeters what is

emmainna [20.7K]

Answer:

base = 8 cm

height = 12 cm

Step-by-step explanation:

We will need the formula for area of a trianlge, which is

A = (1/2)bh where b is the base, and h is the height

We are given two formulas...

"The height of a triangle is 8 centimeters greater than half its base" becomes

h = (1/2)b + 8

"The area of the triangle is 48 square centimeters" becomes

48 = (1/2)bh

Plug the first formula into the second to solve for h

48 = (1/2)b[(1/2) + 8] (h becomes (1/2)b + 8)

Now solve for b

48 = (1/4)b² + 4b

**This is a quadratic euquation. Solve using factoring...

(1/4)b² + 4b - 48 = 0 (subtract 48 from both sides)

b² + 16b - 192 = 0 (multiply by 4 so b² is by itself, it's easier to factor this way)

Now factor...

(b + 24)(b - 8) = 0 (you need two numbers that add to 16 and multiply to -192)

Set each binomial equal to zero and solve for b

b + 24 = 0

b = -24

**this anwser is not valid because b is a length, and you can't have negative length

b - 8 = 0

b = 8

Since the other solution is invalid, the base is b

If the base is b, then the height is...

h = (1/2)b + 8

h = (1/2)(8) + 8

h = 4 + 8

h = 12

8 0

4 years ago