A football pitch is 97 m long and 42 m wide. Bill walks from one corner to another around the outside. Jane walks diagonally acr
1 answer:
The required distance walked by Jane diagonally is 105.7 meters.
Given that,
A football pitch is 97 m long and 42 m wide. Bill walks from one corner to another around the outside. Jane walks diagonally across the pitch. How much further Bill walk is to be determined.
The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
Here,
Length = 97
Width = 42
Diagonal =
Diagonal = 105.7 meters.
Thus, the required distance walked by Jane diagonally is 105.7 meters.
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Answer:
The sound intensity of a whisper is 333.3 times the reference intensity
Step-by-step explanation:
Given : The function gives the intensity of a sound in decibels, where x is the ratio of the intensity of the sound to a reference intensity.
A whisper has a sound intensity of 30 decibels.
To find : Use your graph to help you complete the following statement. The sound intensity of a whisper is times the reference intensity.
Solution :
Graph is attached which shows their intersection at (1000,30).
We can also verify by substituting value.
We have given that a whisper has a sound intensity of 30 decibels.
Therefore, y=30 , Let log base 10
Logarithmic property
The ratio of the intensity of the sound to a reference intensity is 1000 decibels
The sound intensity of a whisper is times the reference intensity is
The sound intensity of a whisper is 333.3 times the reference intensity.
first one is 1 the bottom is 10 2 in 20 3 in 30 4 in 40 5 in 50 6 in 60 7 in 70 8 in 80 9 in 90 then 100
