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Answer:
The original function was transformed by a a horizontal shift to the right in 1 unit, and also a vertical shift upwards of 5 units.
Step-by-step explanation:
Recall the four very important rules regarding translations (shifts) of the graph of functions:
1) In order to shift the graph of a function vertically c units upwards, we must transform f (x) by adding c to it.
2) In order to shift the graph of a function vertically c units downwards, we must transform f (x) by subtracting c from it.
3) In order to shift the graph of a function horizontally c units to the right, we must transform the variable x by subtracting c from x.
4) In order to shift the graph of a function horizontally c units to the left, we must transform the variable x by adding c to x.
We notice that in our case, The original function has been transformed by "subtracting 1 unit from x", and by adding 5 units to the full function. Therefore we are in the presence of a horizontal shift to the right in 1 unit (as explained in rule 3), and also a vertical shift upwards of 5 units (as explained in rule 1).
For Independent Events, P(A) × P(B) = P(A∩B)
so we have, P(A∩B) = 0.4×0.1 = 0.04
P(A') = 1 - 0.4 = 0.6
This information can be represented on a Venn diagram as shown below
P(A'∪B) means the union of everything that is not A with everything that is B
P(A'∪B) = 0.06 + 0.54 + 0.04 = 0.64
so we have, P(A∩B) = 0.4×0.1 = 0.04
P(A') = 1 - 0.4 = 0.6
This information can be represented on a Venn diagram as shown below
P(A'∪B) means the union of everything that is not A with everything that is B
P(A'∪B) = 0.06 + 0.54 + 0.04 = 0.64