Andrew invests $7600 in two different accounts. The first account paid 9 %, the second account paid 14% in interest. At the end

Question

Maslowich

1 year ago

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Andrew invests $7600 in two different accounts. The first account paid 9 %, the second account paid 14% in interest. At the end

of the first year he had earned $829 in interest. How much was in each account?

Mathematics

1 answer:

madreJ [45] · Answer 1 · 2024-09-05T10:16:22+03:00

Andrew invests $7600 in two different accounts. The first account paid 9 %, the second account paid 14% in interest. At the end of the first year he had earned $829 in interest. How much was in each account?

Let

x ------> the amount invested in account that paid 9 %

7,600-x ------> the amount invested in account that paid 14%

we have that

9%=9/100=0.09

14%=14/100=0.14

so

(x)*(0.09)+(7,600-x)*(0.14)=829

solve for x

0.09x-0.14x+1,064=829

0.14x-0.09x=1,064-829

0.05x=235

x=4,700

Find the value of (7,600-x)

7,600-4,700=2,900

therefore

the answer is

<h2> the amount invested in account that paid 9 % was $4,700</h2><h2>the amount invested in account that paid 14% was $2,900</h2>