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3 years ago

Show your work plz luv u

Mathematics

1 answer:

atroni [7]3 years ago

6 0

Answer:

x=7

Step-by-step explanation:

Step 1: Subtract 4x from both sides.

x+30−4x=4x+9−4x

−3x+30=9

Step 2: Subtract 30 from both sides.

−3x+30−30=9−30

−3x=−21

Step 3: Divide both sides by -3.

−3x

−3

−21

−3

The sides of a rhombus are all congruent (the same length.)

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If two dice are rolled, find the probability of rolling two 6's.

djyliett [7]

Total no. of outcomes when two dice are rolled = 36

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Probability of rolling two 6's = 1/36

Hope this helps!

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3 years ago

Find dy/dx if y =x^3+5x+2/x²-1

stiks02 [169]

Differentiate using the Quotient Rule –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

f(x) = x^3+5x+2
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Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

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2 years ago

If the relative frequency of a train being late is 0.15, how often could you expect the train to be late in 100 days?

Natali [406]

Relative frequency is the number of times that the train is late between the total of journeys, so only multiply 0.15*100 =15 times

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3 years ago

Read 2 more answers

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divide both sides by a

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Answer:

Step-by-step explanation:

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