All categories

3 years ago

Show your work plz luv u

Mathematics

1 answer:

atroni [7]3 years ago

6 0

Answer:

x=7

Step-by-step explanation:

Step 1: Subtract 4x from both sides.

x+30−4x=4x+9−4x

−3x+30=9

Step 2: Subtract 30 from both sides.

−3x+30−30=9−30

−3x=−21

Step 3: Divide both sides by -3.

−3x

−3

−21

−3

The sides of a rhombus are all congruent (the same length.)

You might be interested in

What is the value of the expression 3 – a – b when a = 15 and b = –3?

Stolb23 [73]

The answer is -9 c your welcome :)

4 0

3 years ago

Read 2 more answers

PLEASE HELP!! Algebra 2

lawyer [7]

Answer:

Edit:

Yes, based on original equation. (Credit to greenpumpkin for correction)

Step-by-step explanation:

For this problem, we simply need to find the values of x that can make the equation true. So, let's begin by isolating the "x" variable.

sqrt(2x + 13) = x + 5

[sqrt(2x + 13)]^2 = (x + 5)^2

2x + 13 = x^2 + 10x + 25

0 = x^2 + 8x + 12

Note, we can remove the sqrt method by squaring both sides of the equation. Doing this, we see we have a quadratic equation meaning we can apply the quadratic formula to find solutions for x.

[-b +/- sqrt( b^2 - 4(a)(c) ) ] / 2a

Let a = 1, b = 8, and c = 12

[-8 +/- sqrt( (8)^2 - 4(1)(12) ) ] / 2(1)

= [-8 +/- sqrt( 64 - 48 ) ] / 2

= [-8 +/- sqrt(16) ] / 2

= [ -8 +/- 4 ] / 2

So, x = [ -8 + 4 ] / 2 and x = [-8 - 4 ] / 2

x = [-4] / 2 = -2 and x = [-12] / 2 = -6

Hence, the two values of x that can solve this quadratic equation are x = -2 and x = -6.

Therefore, we know that x = -6 is not extraneous, meaning it is a solution to our equation.

Cheers.

----------------------------------------------------

Edit:

Plugging the value of -6 back into the original equation, we get the following:

sqrt(2x + 13) = x + 5

sqrt(2(-6) + 13) = (-6) + 5

sqrt (1) = -1

1 != -1

Given that 1 cannot equal negative 1, we can say that x = -6 is an extraneous solution. (Credit to greenpumpkin for correction)

8 0

3 years ago

You have 5 pairs of pants, 8 shirts, and 3 ties - how many different outfits can you make?

SVEN [57.7K]

First they have to decide on a pair of pants and they have 8 different choices. For each of those choices they have a choice of 5 different shirts, so that gives them 8 times 5 = 40 different pant/shirt combinations. For each those 40 possibilities, they have 3 different ties they could select, so altogether they have 40 times 3 = 120 different outfits.

6 0

3 years ago

I need help ASAP Integrated math II

Molodets [167]

Answer:

$\boxed{ \bold{ \sf{x = 16}}}$