Question

-3x >=9 using the symbols ( [ { in set builder notation the solution set is

Answer 1

The given inequality :

$-3x\ge9$

Simplify :

Multiply both side by (-1) and reverse the inequality :

$\begin{gathered} -3x\ge9 \\ (-1)(-3x)\leq(-1)9 \\ 3x\leq(-9) \end{gathered}$

Divide the inequality by 3:

$\begin{gathered} \frac{3x}{3}\leq\frac{(-9)}{3} \\ x\leq(-3) \end{gathered}$

i.e. x is less than or equal to (-3)

Solution : x ≤ (-3)

so,

x is lies in the half open interval of - infinity to (-3)

Interval Notation : (-infinity, -3]

Answer:

Solution : x ≤ (-3)

Interval Notation : (-infinity, -3]