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Ket [755]
3 years ago
9

13, 3 (y + 3) = 2y + 3

Mathematics
1 answer:
olganol [36]3 years ago
5 0

Answer:

-6

Step-by-step explanation:

3(y+3)=2y+3

3y+9=2y+3

3y-2y=3-9

y=-6

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What is the discriminant of the quadratic equation
pochemuha
-12

Use the equation below

b^2 - 4ac
4 0
4 years ago
How do you solve this?
Allushta [10]
6x^2+25x+14=6x^2+4x+21x+14=2x(3x+2)+7(3x+2)=(2x+7)(3x+2)
7 0
4 years ago
Today, everything at a store is on sale. The store offers a 20% discount.
vesna_86 [32]

Answer:

$14.40

Step-by-step explanation:

a. (18) (80%) = (18) (.80) = $14.40 is discount

b. (x)(.80)= discount price

c. 18/80% =$22.50 is regular price

3 0
3 years ago
The circle with center O has a minor arc BSA with a length of
tangare [24]

Answer:

D. \frac{27\pi}{2} inches.

Step-by-step explanation:

We have been given that the circle with center O has a minor arc BSA with a length of 3\pi^{2} inches. The central angle is 40°.

To find the circumference of circle we will use formula:

\frac{\text{Central angle}}{2\pi}=\frac{\text{Arc length}}{2\pi r}, where 2\pi= measure of 360 degrees in radians and 2\pi r= circumference of circle.  

Let us convert measure of central angle into radians.                        

40^{o}=\frac{40*\pi}{180} =\frac{2\pi}{9}

Upon substituting our given value in the formula we will get,        

\frac{\frac{2\pi}{9}}{2\pi}=\frac{\frac{3\pi}{2}}{2\pi r}

\frac{2\pi}{18\pi}=\frac{3\pi}{4\pi r}    

\frac{1}{9}=\frac{3}{4r}      

Cross multiplying we will get,      

4r=27  

r=\frac{27}{4}

Hence, the radius of our circle is 27/4 inches.  

Since the circumference of circle is 2\pi r. Upon substituting  r=\frac{27}{4} we will get,

2\pi r=2\pi* \frac{27}{4}=\frac{27\pi}{2}

Therefore, circumference of our given circle will be \frac{27\pi}{2} inches and option D is the correct choice.

6 0
3 years ago
A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
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