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erica [24]
3 years ago
15

The graph of f(x)=cos(x) is transformed into a new function, g(x) , by stretching it vertically by a factor of 3 and shifting it

2 units to the left.
What is the equation of the new function g(x) ?
Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

g(x) = 3 cos (x+2)

Step-by-step explanation:

To transform functions use the following formula f(x) = a cos b(x -c) + d where:

  • a stretches the function vertically
  • b compresses or stretches it horizontally
  • c shifts the function left or right
  • d shifts the function up or down

Here a = 3 and c = 2.

So the new function is g(x) = 3 cos (x+2).

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\displaystyle\\&#10;1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\  \\ &#10;1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\  \\ &#10;-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\  \\ \texttt{OR} \\  \\ &#10;-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }


\displaystyle\\&#10;\Longrightarrow ~~1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) =\frac{7}{5} -\frac{11}{2} = \frac{7\times 2}{5\times 2} -\frac{11\times 5}{2\times 5} = \\  \\ &#10;= \frac{14}{10} -\frac{55}{10} = \frac{14-55}{10} =\frac{-41}{10} = -\frac{41}{10}=-\frac{40+1}{10}=\boxed{\boxed{-4\frac{1}{10}}}



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