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Anna [14]
3 years ago
10

The Hundred Years War led to the end of the Middle Ages in the beginning of the

Mathematics
1 answer:
Gre4nikov [31]3 years ago
4 0
It led to the beginning of the Renaissance.
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What is the domain of the function y = 2 VX-5?
tresset_1 [31]

Answer:

<em>R</em>

Step-by-step explanation:

All linear functions have a range and domain of R [ALL REAL NUMBERS].

I am joyous to assist you anytime.

3 0
3 years ago
Jane brought x shirts for $20 each and y skirts for $25 each she spent $210 in all. which equation represents this situation 2
miv72 [106K]

Answer:

Part A

20x + 25y = 210 --> D.

Part B

If jane purchased exactly 4 shirts she must have purchased Exactly ___ skirts. (round to the nearest tenth)

20*4 + 25y = 210 --> y = 5.2

is it possible for jane to purchase exactly 4 shirts? ____(yes or no)

no, because she can't buy 5.2 skirts.

5 0
3 years ago
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Find the critical value zα2/ that corresponds to a 91% confidence level. Question 13 options: a) 1.7 b) 1.95 c) 1.81 d) 2.33 e)
anyanavicka [17]

Answer:

D

Step-by-step explanation:

2.33 I think

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2 years ago
What is the base and height or area? PLS
Rainbow [258]
What do you want exactly i don’t understand the question. Comment and ill solve it
3 0
3 years ago
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1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)

n(X ∪ Y ∪ C') = 145-50

n(X ∪ Y ∪ C') = 95

6 0
3 years ago
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