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3 years ago

Consider the following set of sample data.

1 answer:

3 0

Consider the following set of sample data.

21 29 32 38 38 45 50 64 72 100

For the given data, the mean is 48.9, the median is 41.5, and the mode is 38.

Suppose the observation 21 in the data is mistakenly recorded as 2 instead of 21. For the sample with this error, the mean is 47, the median is 41.5, and the mode is 38.

Suppose the value 21 in the original sample is inadvertently removed from the sample. For the sample with this value removed, the mean is 52, the median is 45, and the mode is 38.

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At the beginning of 2012 Jacob's saving account had $675.20. He deposited $40 each month and earned $66.50 interest for the year

meriva

Not sure but i think it’s B

5 0

3 years ago

What is the slope of a parallel to the graph?

Lelechka [254]

Answer:

Step-by-step explanation:

slopes in parallel are equal

6 0

3 years ago

1.2 if a = -6, b = +4, c = -3 and d = -2 Calculate the value of :-

aalyn [17]

Answer:

a)ab=-6×+4=-24

b)a÷d=-6÷-2=3

c)2bd=2×+4×-2=-16

Step-by-step explanation:

Put the values according to the question

Hope it help you

7 0

3 years ago

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

Find the surface area of the cylinder (please help)

Misha Larkins [42]

Answer:

surface area we can also take it as total surface area

9 is the radius and 5cm is the height . as they asked total surface area we have to take the area of base so tht we can make it as

total surface area = csa of cylinder + area of base

we know that,

2pirh+pir²

pir(2h+r)

pir(2×5+9)

pir(10+9)

pir(19)

22/7×9×19

3762/7

=> 537.42 cm² is the answer.

4 0

2 years ago

Read 2 more answers