Question

The path of a cliff diver can be modeled with the function h(t) = 32+5t-4.9t^2, where h represents her height in meters and t represents the time after she jumps in seconds. What is the swimmer’s height, in meters, two seconds after she jumps?

Answer 1

ANSWER

Swimmer's height two seconds after she jumped is 22.4 meters

STEP-BY-STEP EXPLANATION:

What to find? The swimmer's height after 2 seconds

Given parameters

A modeled function was given

time = 2 seconds

$h(t)\text{ = 32 + 5t - }4.9t^2$

To find the height of the swimmer's, we need to substitute the value of t into the function.

Hence, t = 2 seconds

$\begin{gathered} \text{ t = 2seconds} \\ h(2)=32+5(2)-4.9(2)^2 \\ h(2)\text{ = 32 + 10 - 4.9(4)} \\ h(2)\text{ = 32 + 10 - 19.6} \\ Add\text{ the values together} \\ h(2)\text{ = 42 - 19.6} \\ h(2)=\text{ 22.4 meters} \\ \text{Hence, the swimmer's height two seconds after she jumped is 22.4 meters} \end{gathered}$