Percentage increase in the rate of all rail season tickets to London = 4%
Price of the rail ticket from Cambridge to London increased by = 121.60
Let us assume the price before the increase in the fare = x
Then
4% * x = 121.60 dollars
(4/100) * x = 121.60 dollars
x/25 = 121.60 dollars
x = 25 * 121.60 dollars
= 3040 dollars
So the price of the ticket from Cambridge to London before the increase in price was 3040. I hope the procedure is simple enough for you to understand.
<h3>
Hola! :D ¡te invito a recibir ayuda de un latinoamericano puto!</h3><h2><u>
_____________________________________ </u></h2><h2> 8.35x - 1.5 = 71.98</h2><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>
<u>El -1,5 qlero pasaría al otro lado positivo</u>
<h3> 8.35x = 71.98 + 1.5</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>
<u>Ahora, se suma 71.98 + 1.5 = 73,48</u>
<h3> 8.35x = 73,48</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>
<u>El 8.35 qlero que está multiplicando, pasa al otro lado pero dividiendo</u>
<h3> x = 73,48 ÷ 8.35</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>
<u>Dividimos</u>
<h3> x = 8,8</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2><h2> <u>(b) 8,8</u> es la opción correcta</h2>
Answer:
28.28(simplified from 28.2743338834)
Step-by-step explanation:
area of sector= (center angle/360)*area of circle
we are already given the area of sector as 3/2pi
so
3/2pi=(60/360)*x
(x is area of circle)
3/2pi=4.71238898038
4.71238898038=1/6x
divide both sides by "1/6"
28.2743338834=x
hope this helps!
The answer is $7846.15 since $9.99 times 785.4 cubic inches would be 7846.146 but since we cant get a thousandth of a cent we round it to $7846.15
Answer:
Part A
W W W M W W T W W L W W
W W M M W M T W M L W M
W W T M W T T W T L W T
W W L M W L T W L L W L
W M W M M W T M W L M W
W M M M M M T M M L M M
W M T M M T T M T L M T
W M L M M L T M L L M L
W T W M T W T T W L T W
W T M M T M T T M L T M
W T T M T T T T T L T T
W T L M T L T T L L T L
W L W M L W T L W L L W
W L M M L M T L M L L M
W L T M L T T L T L L T
W L L M L L T L L L L L
Part B
There are 64 possible outcomes. The sample size is 64.
Part C
To find the probability that Erin drinks lemonade one day, tea one day, and water one day, consider all the cases in which L, T, and W occur one time. Because the order doesn't matter in this scenario, these six outcomes from the list represent the desired event: W T L, T W L, T L W, W L T, L W T, and L T W.
The size of the sample space is 64. So, the probability that Erin drinks lemonade one day, tea one day, and water one day is 3/32.
Part D
To find the probability that Erin drinks water on two days and lemonade one day, we consider all the cases in which two Ws and one L occur. Because the order doesn't matter in this scenario, these three outcomes from the list represent the event: W W L, W L W, and L W W.
The size of the sample space is 64. So, the probability that Erin drinks water two days and lemonade one day is 3/64
Step-by-step explanation:
