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muminat
1 year ago
3

It is important to realize that an element’s line spectrum can include emissions at wavelengths throughout the electromagnetic s

pectrum including ultraviolet, visible, and infrared. According to section 2 of the experiment, where will you be collecting data on hydrogen and helium’s line spectra?.
Chemistry
1 answer:
lesya692 [45]1 year ago
7 0

It is important to realize that an element’s line spectrum can include emissions at wavelengths throughout the electromagnetic spectrum including ultraviolet, visible, and infrared then according to section 2 of the experiment visible region collecting data on hydrogen and helium’s line spectra

Electromagnetic spectrum are the spectrum in which electromagnetic radiation are classified wavelength into radio waves,  microwave, infrared, visible light, ultraviolet, X-rays and gamma rays and the types of electromagnetic spectrum are

  • Radio wave : radio waves are used to broadcast the signals
  • Microwave : microwave are used to mobile signals
  • Infrared : infrared transmit heat from difference sourced of fire
  • Visible : visible is the type of electromagnetic radiation
  • Ultraviolet : ultraviolet are used in florescent tube
  • X ray : x ray are used to see the object as well as bodies
  • Gamma rays : gamma rays are used in cell cancer treatment

The hydrogen line spectra fall between wavelength, 410 nm to 656 nm. The helium line spectra fall between wavelength, 400 nm to 781 nm and this two fall in the visible region of line spectra

Know more about hydrogen and helium’s line

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Answer:

Approximately 53.3\; \rm g.

Explanation:

Lookup Avogadro's Number: N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1} (three significant figures.)

Lookup the relative atomic mass of \rm H, \rm S, and \rm O on a modern periodic table:

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(For example, the relative atomic mass of \rm H is 1.008 means that the mass of one mole of \rm H\! atoms would be approximately 1.008\! grams on average.)

The question counted the number of \rm H_2SO_4 molecules without using any unit. Avogadro's Number N_{\rm A} helps convert the unit of that count to moles.

Each mole of \rm H_2SO_4 molecules includes exactly (1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23} of these \rm H_2SO_4 \! molecules.

3.27 \times 10^{23} \rm H_2SO_4 molecules would correspond to \displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of \rm H_2SO_4 gives the mass of each mole of \rm H_2SO_4\! molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}.

Calculate the mass of approximately 0.541389\; \rm mol of \rm H_2SO_4:

\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}.

(Rounded to three significant figures.)

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