The balanced equation for the reaction is as follows
2H₂ + O₂ --> 2H₂O
stoichiometry of H₂ to O₂ is 2:1
number of H₂ moles - 30.0 g / 2 g/mol = 15 mol
number of O₂ moles - 80.0 g / 32 g/mol = 2.5 mol
limiting reactant is the reagent in which only a fraction is used up in the reaction
if H₂ is the limiting reactant
if 2 mol of H₂ requires 1 mol of O₂
then 15 mol of H₂ requires 1/2 x 15.0 = 7.5 mol of O₂
but only 2.5 mol of O₂ is required
this means that O₂ is the limiting reagentt and H₂ is in excess
H2 is a covalent bond. Each hydrogen atom shares its single electron to the other, so each hydrogen has two valence electrons (full outer shell).
Answer:
The cathode is the electrode where the reduction takes place.
Explanation:
Cell has three components:
an electrolyte and two electrodes which is a cathode and an anode.
Electrolyte is usually solution of the water or other solvents in which the ions are dissolved.
<u>In electrolytic cell:</u>
Negatively charged electrode is the cathode where the process of reduction takes place.
Positively charged electrode is the anode where the process of oxidation takes place.
<u>In galvanic cell:</u>
Positively charged electrode is the cathode where the process of reduction takes place.
Negatively charged electrode is the anode where the process of oxidation takes place.
<u>So, the correct answer is - The cathode is the electrode where the reduction takes place.</u>
The formula for the self ionization of water is 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq)
The hydronium (H₃O⁺) is usually just referred to as a hydrogen ion or a proton (H⁺) and hydroxide (OH⁻) doesn't have another name that I am aware of. These ions do stay in solution. However the concentrations are really small and the equilibrium constant (K(w)) is 1×10⁻¹⁴.
I hope this helps. Let me know if anything is unclear.
