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Goryan [66]
3 years ago
13

How many moles of carbon dioxide can be produced when 3.05 of calcium carbonate are heated​

Chemistry
1 answer:
vredina [299]3 years ago
3 0

Answer:

0.0305mol

Explanation:

CaCO3 ---> CaO + CO2

Mass of CaCO3 mol = 40 + 12 + (16 x 3) = 100g/mol

Number of CaCO3 moles heated = 3.05/100 = 0.0305 mol

One CaCO3 mol produces 1 mol CO2

Therefore 0.0305mol  of CO2 produced.

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Question 2(Multiple Choice Worth 3 points) What happens to the rate of most reactions as the reaction progresses? The rate remai
Sav [38]

Answer: -

The rate decreases as the concentration of the reactants decreases

Explanation: -

A reaction involves change of the reactants into products.

Initially there is only reactants. So the rate if reaction is high.

After some time there are products. So the amount of reactant is less.

Reactions involve collisions of reactant molecules. As the reactant amount decreases, collisions between the reactants decreases. As such the rate of reaction decreases with the progress of the reaction.

3 0
3 years ago
What word best describes volume
alekssr [168]

Answer:

volume is the amount of space something occupies

Explanation:

7 0
3 years ago
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True or False: the force of attraction that holds two atoms together is called a chemical bond
Genrish500 [490]
The answer is true.
5 0
3 years ago
What is the ratio of lactic acid (Ka = 1.37x^10-4) to lactate in a solution with pH =4.29
hram777 [196]

Henderson–Hasselbalch equation is given as,

                                         pH  =  pKa  +  log [A⁻] / [HA]   -------- (1)

Solution:

Convert Ka into pKa,

                                         pKa  =  -log Ka

                                         pKa  =  -log 1.37 × 10⁻⁴

                                         pKa  =  3.863

Putting value of pKa and pH in eq.1,

                                         4.29  =  3.863 + log [lactate] / [lactic acid]

Or,

                   log [lactate] / [lactic acid]  =  4.29 - 3.863

                   log [lactate] / [lactic acid]  =  0.427

Taking Anti log,

                             [lactate] / [lactic acid]  =  2.673

Result:

           2.673 M  lactate salt when mixed with 1 M Lactic acid produces a buffer of pH = 4.29.

6 0
3 years ago
What pressure is required to compress 156.0 liters of air at 2.00 atmosphere into a cylinder
garik1379 [7]

Answer:

option B.

Explanation:

Given,

V₁ = 156 L

P₁ =2 atm

Now, in the cylinder

P₂ = ?

V₂ = 36

Using relation between pressure and volume

\dfrac{P_1}{V_2}=\dfrac{P_2}{V_1}

\dfrac{2}{36}=\dfrac{P_2}{156}

P_2 = 8.67\ atm

Hence,  pressure is equal to 8.67 atm.

Hence, the correct answer is option B.

7 0
3 years ago
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