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Marizza181 [45]
3 years ago
15

By making several measurements with the same balance, a chemist obtained values of 5.224 g, 5.235 g, and 5.259 g for the mass of

a sample. Without knowing the actual mass of the sample, we can tell that these measurements have .
a) good precision
b) good accuracy
c) poor precision
d) poor accuracy
Chemistry
1 answer:
stepan [7]3 years ago
6 0

Answer:

a) Measurements have a good precision.

Explanation:

Accuracy is the proximity of the data to the value considered as real, in this situation we do not know the real value and we do not know if the data is accurate or not, so we can discard options b and d.

Now, precision is the proximity of the data obtained among themselves and that is what we can observe, so the appropriate answer is the option a.

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algol [13]

Answer:2,3 -dimethyl-2-butenr

Explanation:

3 0
3 years ago
If the mass of the object below is 28g, what is the density of the object below. Units are in cm below. Please round your answer
Murljashka [212]

Answer:

d = 0.93 g/cm³

Explanation:

Given data:

Mass of object = 28 g

Volume of object = 3cm×2cm×5cm

density of object = ?

Solution:

Volume of object = 3cm × 2cm ×5cm

Volume of object = 30 cm³

Density of object:

d = m/v

by putting values,

d = 28 g/ 30 cm³

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3 0
3 years ago
How many grams of glucose are needed to prepare 144.3 mL of a 1.4%(m/v) glucose solution?
Montano1993 [528]

Answer:

2.0202 grams

Explanation:

1.4% (m/v) glucose solution means: 1.4g glucose/100mL solution.

so ?g glucose = 144.3 mL soln

Now apply the conversion factor, and you have:

?g glucose = 144.3mL soln x (1.4g glucose/100mL soln).

so you have (144.3x1.4/100) g glucose= 2.0202 grams

6 0
3 years ago
Read 2 more answers
The generic metal a forms an insoluble salt ab(s) and a complex ac5(aq). the equilibrium concentrations in a solution of ac5 wer
Leno4ka [110]

Assuming that the reaction from A and C to AC5 is only one-step (or an elementary reaction) with a balanced chemical reaction of:

<span>A + 5 C  --->  AC5 </span>

Therefore the formation constant can be easily calculated using the following formula for formation constant:

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<span>Kf = [AC5] / [A] [C]^5                     </span>

---> Any coefficient from the balanced chemical reaction becomes a power in the formula

Substituting the given values into the equation:

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Kf = 6,209,213,231

or in simpler terms

<span>Kf = 6.21 * 10^9                  (ANSWER)</span>

3 0
3 years ago
1. If the frequency of a wave increases from 2 Hz to 4 Hz without the wavelength changing, how will the wave speed change?
maw [93]

Answer:

Given expression: 6(2b-4). To find the value of 6(2b-4) at b= 5, we need to substitute the b=5 in the expression, we get….Therefore, the value of 6(2b-4) is 36, when b=5.

Explanation:

Given expression: 6(2b-4). To find the value of 6(2b-4) at b= 5, we need to substitute the b=5 in the expression, we get….Therefore, the value of 6(2b-4) is 36, when b=5.

8 0
2 years ago
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