Answer:
Therefore the probability that he was taught by method A is 0.78.
Explanation:
<h3>
Probability:</h3>
The ratio of the number of favorable outcomes to the number of all possible outcomes.
<h3>
Bayes' Rule:</h3>
If the events 
,
, .....
from a portion of a sample space S and A is any events of A, then
Given that,
There are two available method for teaching A and B.
The failure rate for A is 35%
That is P(F|A) =35%=0.35
The failure rate for B is 15%
That is P(F|A) =15%=0.15
A used 40% of the time.
P(A)=40%=0.40
B used 60% of the time.
P(A)=60%=0.60
To find P(A|F) , we use the Bayes's rule.
=0.78
Therefore the probability that he was taught by method A is 0.78.
3.141592653
Also written as 22/7 as a fraction
Answer:
y = x/10 + 43/10
Step-by-step explanation:
y - y1/ x - x1 = y2 - y1/ x2 - x1
y - 4/ x +3 = 5 - 4/7 + 3
y - 4 / x + 3 = 1/10
10(y - 4) = x + 3
10y - 40 = x + 3
10y = x + 43
y = x/10 + 43/10
Answer:
I have exams too well cba's
Step-by-step explanation:
This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation.
-4(2y) + 11y = 15
-8y + 11y = 15
3y = 15 ; y = 5
Substitute this value of y to either the first or second equation.
x = 2(5) = 10
The ordered pair is therefore (10,5).
