Question

A boy stands 12 metres from the foot of the building and observes the angle of elevation of the top of the building. The height is of the building is approximately

Answer 1

Answer:

10.07 meters

Step-by-step explanation:

We are given that the angle of elevation is 40° and the boy is 12 meters from the building.

This means that in order to figure out the height of the building, we must use the tangent function which states that $tan(\theta)=\frac{opposite}{adjacent}$.

The opposite side in this case is the height of the building in relation to the angle and the adjacent side is the distance the boy is away from the building.

Therefore, we can find the height of the building by plugging in our known information and solving for the opposite side:

$tan(\theta)=\frac{opposite}{adjacent}$

$tan(40^\circ)=\frac{x}{12}$

$12tan(40^\circ)=x$

$x=12tan(40^\circ)$

$x\approx10.07$

Therefore, the height of the building is approximately 10.07 meters.

Answer 2

Answer:

What!!

Step-by-step explanation: