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larisa [96]
3 years ago
11

C3H8O3 - glycerol Major species present when dissolved in water

Chemistry
2 answers:
loris [4]3 years ago
4 0

Answer:

\rm C_{3}H_{8}O_{3}(aq)

Explanation:

Glycerol is a covalent molecule. The major species in an aqueous solution will be hydrated glycerol molecules.

\rm C_{3}H_{8}O_{3}(l) \longrightarrow \, C_{3}H_{8}O_{3}(aq)

zysi [14]3 years ago
3 0

<u>Answer:</u> Water and glycerol are the major species that are present when dissolved in water.

<u>Explanation:</u>

Glycerol is a covalent compound because it is formed by the sharing of electrons between carbon, oxygen and hydrogen atoms.

Covalent compounds when dissolved in water behave as non-electrolytes.

Non-electrolytes are defined as the species which does not get dissociated into its ions when dissolved in water.

Thus, when glycerol is dissolved in water, the major species which must be present in the solution are water and glycerol itself.

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Gold cylinder has a mass of 75 g and a specific heat of 0.129J/G degrees Celsius it is heated to 65°C and then put in 500 g of w
nadezda [96]
<h3>Answer:</h3>

89.88° C

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of gold cylinder as 75 g
  • specific heat of gold is 0.129 J/g°C
  • Initial temperature of gold cylinder is 65°C
  • Mass of water is 500 g
  • Initial temperature of water is 90 °C

We are required to calculate the final temperature;

  • We know that Quantity of heat is given by the product of mass, specific heat capacity and change in temperature.
  • That is, Q = m × c × ΔT
<h3>Step 1: Calculate the quantity of heat absorbed by the Gold cylinder</h3>

Assuming the final temperature is X° C

Then; ΔT = (X-65)°C

Therefore;

Q = 75 g × 0.129 J/g°C × (X-65)°C

   = 9.675X - 628.875 Joules

<h3>Step 2: Calculate the quantity of heat released by water</h3>

Taking the final temperature as X° C

Change in temperature, ΔT = (90 - X)° C

Specific heat capacity of water is 4.184 J/g°C

Therefore;

Q = 500 g × 4.184 J/g°C × (90 - X)° C

  = 188,280 -2092X joules

<h3>Step 3: Calculate the final temperature, X°C</h3>

we know that the heat gained by gold cylinder is equal to the heat released by water.

9.675X - 628.875 Joules = 188,280 -2092X joules

2101.675 X = 188908.875

              X = 89.88° C

Thus, the final temperature is 89.88° C

3 0
3 years ago
The atmospheric pressure on a mountain is 550 mmHg and 1
andrew11 [14]

Answer:

0.72

Explanation:

if 760=1

550=x

=550÷760= 0.72 in two s.f

5 0
3 years ago
A substance that is ______ will NOT dissolve in a solvent. A) freezing B) insoluble C) evaporating D) soluble
Alexxandr [17]

Answer:

insoluble

Explanation:

4 0
3 years ago
Read 2 more answers
Which type of crust combination CANNOT undergo subduction?
nordsb [41]

Answer:

the correct answer is B

Explanation:

Subduction: they present if or if two Convergent edges or subduction zones (destructive edges). Where two plates collide, due to having movements with opposite directions, the denser one sinks below the less dense one along what is known as the subduction zone; the subducting plate goes into the mantle, heating up and partially melting generating magma that rises to the surface. A subduction zone is characterized by deformation, volcanism, mountain formation, metamorphism, seismic activity, and significant mineral deposits.

This phenomenon occurs between oceanic plates or between a continental and an oceanic plate, since when there is a difference in density they subduct.

In the event that the edges of two continental plates collide, it would be OBDUCTION, which is another phenomenon other than subduction. mantle does not produce the correct subduction process, as the movement must be absorbed in some way, this is carried out by vertically deforming both plates, which are joined by a suture area, forming an inner mountainous belt and Suffering, in addition, numerous earthquakes. This process is very important, since it is the one that has given rise to the highest mountain ranges on Earth and is a very active process at present (Ex: Los Alpes, Los Montes Urales and Montes Himalaya).

6 0
3 years ago
Carbon-14 has a half-life of 5,730 years. After how many half-lives will 120 grams of Carbon-14 decay to 15 grams?
Sergeu [11.5K]
After 17190 years, Carbon-14 will reach a mass of 15 grams.

Pi is your initial amount (120 grams)
0.5 as your exponential base represents your HALF life hence 0.5
t represents the time elapsed
c represents your given half life value of (5730)
P(t) represents the exponential function of your half life

120/2 =60
60/2 = 30
30 /2 = 15

As you can see above, 3 half lives of 5730 years EACH degraded the carbon-14 to 15 grams. You divide each number by two as it is a HALF life.

P(t)= Pi (0.5) ^t/c
P(17190) = 120 (0.5) ^17190/5730
P(17190) = 120 (0.5) ^3
P(17190) = 15 grams

So your answers should be 3 half lives or after 17190 years have elapsed!
5 0
4 years ago
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