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2 years ago

A substance that is ______ will NOT dissolve in a solvent. A) freezing B) insoluble C) evaporating D) soluble

Chemistry

2 answers:

kiruha [24]2 years ago

8 0

Answer:

B)Insoluble

Explanation:

A substance that does not dissolve in a solvent is insoluble. Process of Dissolving: Solvent particles surround solute particles to form a solution in a process called solvation. (This dissolving process in water is called hydration.)

Alexxandr [17]2 years ago

4 0

Answer:

insoluble

Explanation:

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If 120.3 mL of water is shaken with oxygen gas at 2.1 atm, it will dissolve 0.0043 g O2. Estimate the Henry's law constant for t

nikklg [1K]

<u>Answer:</u> The Henry's law constant for oxygen gas in water is $1.702\times 10^{-5}g/mL.atm$

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{O_2}=K_H\times p_{O_2}$

where,

$K_H$ = Henry's constant = ?

$C_{O_2}$ = solubility of oxygen gas = $0.0043g/120.3mL$

$p_{O_2$ = partial pressure of oxygen gas = 2.1 atm

Putting values in above equation, we get:

$0.0043g/120.3mL=K_H\times 2.1atm\\\\K_H=\frac{0.0043g}{120.3mL\times 2.1atm}=1.702\times 10^{-5}g/mL.atm$

Hence, the Henry's law constant for oxygen gas in water is $1.702\times 10^{-5}g/mL.atm$

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2 years ago

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2 years ago

I NEED HELP FAST !The density of aluminum is 2.70 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of aluminum?

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3 years ago

10mL volume of 75mM EtOH is necessary for an experiment. What volumes of 1M EtOH and water should be mixed to obtain the working

kenny6666 [7]

Answer: Volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration.

Explanation:

According to the dilution law,

$C_1V_1=C_2V_2$

where,

$C_1$ = molarity of stock solution = 1M

$V_1$ = volume of stock solution = ?

$C_2$ = molarity of diluted solution = 0.075 M (1mM=0.001M)

$V_2$ = volume of diluted solution = 10 ml

Putting in the values we get:

$1M\times V_1=0.075M\times 10ml$

$V_1=0.75ml$

Thus 0.75 ml of 1M EtOH is taken and (10-0.75)ml = 9.25 ml of water is added to make the volume 10ml.

Therefore, volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration

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3 years ago