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Given 1 molecule of glutamate, how much atp can you form by oxidative phosphorylation?

hammer [34]

1 molecule of glutamate can form 7.6 ATP can be formed by oxidative phosphorylation .

<h3>What is oxidative Phosphorylation ?</h3>

In the process of oxidative phosphorylation, oxygen is consumed as electrons are transferred through the mitochondrial electron transport chain and ATP is produced.

The bulk of the ATP required for higher animals and plants to sustain life is produced by oxidative phosphorylation, which is also in charge of creating and preserving metabolic equilibrium.

The glutamate carrier recycles glutamate outside of mitochondria (T9). One aspartate and 7.6 ATP are made at the best return for each glutamine.

To learn more about oxidative phosphorylation, refer to the below link:

brainly.com/question/25765324

#SPJ4

5 0

1 year ago

Which reactant will be used up first if 78.1g of o2 is reacted with 62.4g of c4h10?

dlinn [17]

Answer:

Reagent O₂ will be consumed first.

Explanation:

The balanced reaction between O₂ and C₄H₁₀ is:

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:

C₄H₁₀: 2 moles
O₂: 13 moles
CO₂: 8 moles
H₂O: 10 moles

Being:

C: 12 g/mole
H: 1 g/mole
O: 16 g/mole

The molar mass of the compounds that participate in the reaction is:

C₄H₁₀: 4*12 g/mole + 10*1 g/mole= 58 g/mole
O₂: 2*16 g/mole= 32 g/mole
CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole
H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:

C₄H₁₀: 2 moles* 58 g/mole= 116 g
O₂: 13 moles* 32 g/mole= 416 g
CO₂: 8 moles* 44 g/mole= 352 g
H₂O: 10 moles* 18 g/mole= 180 g

If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

$mass of O_{2} =\frac{416grams of O_{2}*62.4 grams ofC_{4}H_{10} }{116 grams of C_{4}H_{10}}$

mass of O₂= 223.78 grams

But 21.78 grams of O₂ are not available, 78.1 grams are available. Since you have less mass than you need to react with 62.4 g of C₄H₁₀, <u><em>reagent O₂ will be consumed first.</em></u>

3 0

3 years ago

Q05 the "atomic number" of an atom is determined by the number of ________ it has.

Alexxx [7]

The atomic number of an atom is determined by the number of protons it has..

It is also the whole number shown on the periodic table

6 0

4 years ago

What do organs combine to form? organ systems cells tissues organisms

FrozenT [24]

Answer:

Higher levels of organization are built from lower levels. Therefore, molecules combine to form cells, cells combine to form tissues, tissues combine to form organs, organs combine to form organ systems, and organ systems combine to form organisms.

8 0

3 years ago

Read 2 more answers

How much oxygen will contain the same number of atoms as the number of molecules in 73 g of HCI?

expeople1 [14]

Answer:

64g of O2.

Explanation:

We'll begin by calculating the number of molecules in 73g if HCl.

This is illustrated below:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of HCl also contains 6.02×10²³ molecules

1 mole of HCl = 1 + 35.5 = 36.5g

Thus, if 36.5g of HCl contains 6.02×10²³ molecules, then 73g of HCl will contain = (73 x 6.02×10²³)/36.5 = 1.204×10²⁴ molecules.

Therefore, 73g of HCl will contains 1.204×10²⁴ molecules.

Now, we shall determine the mass of oxygen that will contain 1.204×10²⁴ molecules.

This can be obtained as follow:

1 mole of O2 = 16x2 = 32g

32g of O2 contains 6.02×10²³ molecules.

Therefore, Xg of O2 will contain 1.204×10²⁴ molecules i.e

Xg of O2 = (32 x 1.204×10²⁴)/6.02×10²³

Xg of O2 = 64g

Therefore, 64g of O2 will contain the same number of molecules (i.e 1.204×10²⁴ molecules) in 73g of HCl.

5 0

3 years ago