(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)
This becomes easier if we switch to fractional exponents:
5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)
Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.
1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)
That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:
1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5
Answer:
k=20
Step-by-step explanation:
when x approaches 4, the denominator x-4 approaches 0
if the denominator is 0, it means that this is invalid
if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit
so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4
so x^2 + x - k = 0 when x = 4
4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20
The answer to 6 2/3 divide by 9 2/3 should equal to 20/29.
I think y=2x^2+8x-10
In case u don't know ^2 means square so don't put ^2 put the 2 next to the x on top cuz some ppl get confused
hoped I helped!:)
Sorry, i dont know that one. i wish i could help ya