G^−m ÷ g^n
1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)
Answer:
D. (7.4); scale factor 2.
I’m not sure how to explain this but I’ve done it last year.
Hope that helps.
Answer: 7776p^2q
Step-by-step explanation:
Talk about the hot hand theory relates to basketball state.
