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Afina-wow [57]
4 years ago
5

Find the radius of each circle if the area of the sector is 12

Mathematics
1 answer:
lbvjy [14]4 years ago
5 0
Root: A/2 is the equation 
your answer is 1.38 
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Translate each sentence into an equation.
iogann1982 [59]
Answers

1. 1/4 x M-6= (m+9)x2


Ps. Couldn’t do 4
5 0
2 years ago
Read 2 more answers
Write as an algebraic expression: <br><br> 1) a% of 80 <br><br> 2) 17% of b <br><br> 3) a% of b
Anna35 [415]
1) 4a/5
a% of 80 = a% (80) = (a/100)(80) = 80a/100 = 4a/5

2) 17b/100 or 0.17b
17% of b = (17/100)(b) = 17b/100 [ = 0.17b ]

3) ab/100
a% of b = (a/100)(b) = ab/100
5 0
3 years ago
Please help me :((( it’s geometry
NikAS [45]

\tt Step-by-step~explanation:

\tt Area:

To solve for the area of a triangle, we multiply the length and height, then divide that by two. L = 10. H = 7.

\tt 10*7=70\\70/2=35\\35=A

\tt Perimeter:

\tt Step~1:

To solve for the perimeter, or edges, of the triangle, we need to use the Pythagorean Theorem: a² + b² = c² to solve for the third side. We already know two measures: 10 and 7. Now we need to square them, add them together to get c², then take the root of that number.

\tt 7^2=49\\10^2=100\\100+49=\sqrt{149}\\\sqrt{149

We cannot simplify √149, so we either leave it, or round it.

\tt \sqrt{149}\\12.2066

This is rounded to the nearest 10,000.

\tt Step~2:

Now that we have the measure of the longest side, we can add all three sides together to get the perimeter of the triangle.

\tt 10+7+\sqrt{149}=17+\sqrt{149}=P\\Rounded~to~the~nearest~1,000th:~29.207=P

\large\boxed{\tt Our~final~answer: ~A=35,~P=17+\sqrt{149}}

5 0
3 years ago
Which Expression represents the following algebraic statement?
harkovskaia [24]

Answer:

7(x+5)-(2xy^2)

that's how you would write the equation

4 0
3 years ago
Please help me with this question
mars1129 [50]

Answer:

<h2>4/5</h2>

Step-by-step explanation:

Look at the picture.

sine=\dfrac{opposite}{hypotenuse}

We need a hypotenuse length.

Use Pythagorean theorem:

hypotenuse^2=leg^2+leg^2

We have

leg=9,\ leg=12,\ hypotenuse=x

Substitute:

x^2=9^2+12^2\\\\x^2=81+144\\\\x^2=225\to x=\sqrt{225}\\\\x=15

For the sine we have:

opposite=12, hypotenuse=15

Substitute:

\sin\alpha=\dfrac{12}{15}=\dfrac{12:3}{15:3}=\dfrac{4}{5}

3 0
3 years ago
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