Answer:
to find V in this equation
4 = -6 + V
V = 10
hope it helps
Answer:
15/4 x-y=-24
Step-by-step explanation:
the standard form is ax+by=c
two points (x1,x2) , (y2,y1)
x1=-8 x2=-6
y1=-4 y2=9
find slope m: y2-y1/x2-x1
m=9-(-6)/-4-(-8)
m=15/4
find b: take any point(-8,-6)
y=mx+b
-6=15/4 (-8)+b
-6=-30+b
b=-6+30
b=24
y=15/4 x+24
standard form: y-15/4x=24
OR : 15/4 x-y=-24
It is the first one because fist you reflect it to the right across the y axis, then you reflect it down across the x axis, and last but not least, you reflect it left across the y axis where it is now
hope this is helpful! :)
There were 4 musicians in the bad last month
Part (i)
I'll use H in place of T to represent the heat of the object. That way there isn't a clash of variables lowercase t vs uppercase T.
The equation we're working with is updated to:
H(t) = 22 + a*2^(bt)
Plugging in t = 0 as the initial time value should lead to the temperature being H = 86 degrees Celsius.
So,
H(t) = 22 + a*2^(bt)
86 = 22 + a*2^(b*0)
86 = 22 + a*2^0
86 = 22 + a*1
86 = 22 + a
a+22 = 86
a = 86-22
a = 64
<h3>Answer: 64</h3>
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Part (ii)
We'll use the value of 'a' we found earlier. Plus we'll use the fact that H = 28 when t = 0.5 (since 30 min = 30/60 = 0.5 hr).
H(t) = 22 + a*2^(bt)
28 = 22 + 64*2^(b*0.5)
28-22 = 64*2^(0.5b)
64*2^(0.5b) = 6
2^6*2^(0.5b) = 6
2^(6+0.5b) = 6
log( 2^(6+0.5b) ) = log(6)
(6+0.5b)*log(2) = log(6)
6+0.5b = log(6)/log(2)
6+0.5b = 2.5849625
0.5b = 2.5849625-6
0.5b = -3.4150375
b = -3.4150375/(0.5)
b = -6.830075
<h3>Answer: Approximately -6.830075</h3>
