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1 year ago

15

The distance between -2 1/2 - (-3)

1 answer:

Ierofanga [76]1 year ago

3 0

The distance between -2 1/2 - (-3)

-2 1/2 + 3

1/2

______________________

Answer

1/2

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Solve x2 – 10x + 25 = 35 for x.

Galina-37 [17]

$x^2-10x+25=35\\\\x^2-2\cdot5\cdot x + 5^2=35\ \ \ |\text{use:}\ (a-b)^2=a^2-2ab+b^2\\\\(x-5)^2=35\to x-5=\pm\sqrt{35}\ \ \ |+5\\\\\boxed{x=5-\sqrt{35}\ \vee\ x=5+\sqrt{35}}$

$\text{other method}\\\\x^2-10x+25=35\\\\x^2-5x-5x+25=35\\\\x(x-5)-5(x-5)=35\\\\(x-5)(x-5)=35\\\\(x-5)^2=35\\.....$

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4 years ago

SOMEONE HELP !!! Please

Lelu [443]

Answer:

x = ± $\sqrt{8}$ - 2

Step-by-step explanation:

x² + 4x = 4

to complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 4 + 4

(x + 2)² = 8 ( take square root of both sides )

x + 2 = ± $\sqrt{8}$ ( subtract 2 from both sides )

x = ± $\sqrt{8}$ - 2

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1 year ago

For each of the following vector fields

olga nikolaevna [1]

(A)

$\dfrac{\partial f}{\partial x}=-16x+2y$

$\implies f(x,y)=-8x^2+2xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=10y$

$\implies g(y)=5y^2+C$

$\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}$

(B)

$\dfrac{\partial f}{\partial x}=-8y$

$\implies f(x,y)=-8xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x$

$\implies \dfrac{\mathrm dg}{\mathrm dy}=x$

But we assume $g(y)$ is a function of $y$ alone, so there is not potential function here.

(C)

$\dfrac{\partial f}{\partial x}=-8\sin y$

$\implies f(x,y)=-8x\sin y+g(x,y)$

$\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=4y$

$\implies g(y)=2y^2+C$

$\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}$

For (A) and (C), we have $f(0,0)=0$ , which makes $C=0$ for both.

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3 years ago

Who are the characters in Macbeth?

Schach [20]

Answer:

There are A LOT of characters in Macbeth, but here they are.

Step-by-step explanation:

Macduff

Macbeth

Lady Macbeth

King Duncan

Banquo

Malcolm

Three Witches

Fleance

Donalbain

Lady Macduff

Young Siward

Third Murderer

Macduff's son

Seyton

Doctor

Second Murderer

Servant

Old man

Captain

Children

Ross

Angus

Lennox

Porter

Gentlewoman

First murderer

That's all that I can think of! Hope I could help you out :)

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3 years ago

Find the coordinates of midpoint e. Please help

Sedaia [141]

Answer:

(-2a, -2b)

Step-by-step explanation:

( $\frac{-3a+(-a)}{2}$ , $\frac{b+(-5b)}{2}$ )

( $\frac{-4a}{2}$ , $\frac{-4b}{2}$ )

$(-2a$ , $-2b)$

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3 years ago